human factors doubt
 

its Always IAS (please give all the four options )

Differential Pressure
and for Altimeter its static pressure




:ok:

@planeboy_777

sorry sir,my bad. the options are-
1)CAS
2)EAS
3)GS
4)TAS

Thnx!!!

its CAS...

if there is a misunderstanding due to uncommon language between the controller and the pilot .what instruction will be issued for the a/c to make him land??

Urgent help required !
 

:eek:
I dont know if I'm the only one who made this frivolous discovery on the CX2 but its been bugging me ever since!

HAS anybody had any problem calculating Headwind/tailwind & crosswind components and tallying the answers with the ones using actual fromula ?

HWC/TWC = windspeed x Cos Xdeg,
CWC= windspeed x Sin Xdeg. ( for those who didn't know!)

say for eg. Hdg= 30 deg, W/V = 60/30.

solve this using the formula and CX2, ANSWER DOESN'T MATCH!

COULD ANYBODY PLEASE OFFER A VALUABLE SOLUTION ?

With an true airspeed of 194 kt and a vertical speed of 1 000 ft/min, the climb gradient is about: Ans 3 degrees
can anyone please solve this question??

rule of thumb for calculating climb or descend gradient :

ROC or ROD / Groundspeed = X %

in your example : TAS can be assumed as Groundspeed ,
hence 1000fpm/ 194 kts = 5.15 % or 3 degrees ( ANSWER!)

...can anybody please solve Cloudripper's query , strange but I've never realised it until now too!

@cobracommander
Thnx for the solution.I understand getting 5.15% as Climb gradient but the doubt is how did you get 3 degrees?

@Aviator4u,
Use Trigonometry mate.
Convert 194kts, into ft/min. That would be your adjacent side.
a vertical speed of 1000 ft/min would be your opposite.

tan (climb angle) = 1000/194 x 6080/60

apply tan inverse, to get the answer of 2.92 degrees, round it off to 3.

Given
TAS = 140
True Heading = 302
W/V = 45(T)/45Kt

what is the Drift angle and Ground Speed?

Anyone with ideas how to solve this?

@climb gradient
 

climb gradient = (rate of climb * 6000)/ (tas*6080)

GLIDE PATH (DEGREES) = ((GLIDE PATH (%)*60))/100

CLIMB GRAD = (1000*6000)/(194*6080) = 5.08

GP(DEG) = (5.08 * 60 )/100 = 3 DEGREES
:ok:

@ cloud ripper
 

The concept here apply's of VELOCITY TRAIANGLE
1. True wind component
2. Effective wind component

In true wind component Along track and across track components co-exists and hence the formula of cos and sin gives the right ans.

However, when we talk about HWC and TWC Effective wind components come into the picture.
acc to which GS-TAS= wind component

this wind component if Neg implies a HWC and if Pos implies TWC.

Now this VALUE of the wind component can be diff for calculating HWC and TWC.

http://s1227.photobucket.com/albums/...harsh_aviator/

In this picture it is shown that how effective wind components often differ.

The TAS is acting along the heading but the effect of the TAS along the track will be TAS cos drift. TAS cos of drift is less the TAS . To get the GS the true component will have to be applied to this.
Hence the difference between the true n effective wind component is TAS- TAS cos drift.
Hence Effective wind component is always less favourable unless there is no drift, ie, in flying directly UPwind and downwind.

@harsh786techy
 

?where did u read up info on triangle of vel?
also are these kinda questions asked in cae exam?

The information is from GSP Navigation.

If these questions asked or not i do not know but it depends how the question is framed. Generally a simple theory question will be asked if "if asked".

NDB range
 

what is the formula to calculate range of NDB?

Q.What is the range of NDB of power 10KW? Is it same over sea and land?

Range over water= 3X Square root(wattage)
land= 2X square root(wattage).

clearly, range over water is greater then land.

@harsh786techy-
Thank you for you reply,but acc to your formula range in the case of 10 KW should be 3*SQRT(10000) which works out to be 300 NM and it is nowhere close to the answer options which are-50NM,100NM,500NM,1000NM

The answer to be marked for this ques should be 100. for solving such problems simply square root of wattage is considered.
However for the comparison the factors of 2 and 3 are considered. i am sure the ans must be 100. if its not then i will look into it.

@harsh
 

you are correct mate it has to be 100nm