Indigo Call letters for Freshers
Join Date: Jan 2011
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INSTRUMENT QUESTIONS
Q1. The ISA pressure for 18000feet are:
anS. 506hpa
plz Someone guide how to cal pressure change with altitude.
Q2.An inc. of 0.15Mach result in an inc. of 93kt TAs of an a/c. the local speed of sound is:
ANs-620KTs
PLZ guide how to solve this problem
Q3.An a/c is flying at 400ft from a high temp area to a cold temp area where the temp diff. is 20degree. what will be actual height of a/c:
Ans-3680feet
{As we are going from low density to high density area........the true height should decrease right!....i get that point but how to calculate barometric error......because QNH is not given....only temprature diff of 20degree is given.........plz explain}
Q4.An inc. of 0.15Mach number result in an inc. of93kts in TAs.if temp deviation from IsA Is +9DEGREE,the FL is:
ANs--FL220{plz explain}
Q5.The atmospheric pressure at FL70 in a "standard +10" atmosphere is:
ANs---781.85HPa{plz expalin}
Q6.Cruising at FL390,M0.84 is found to give a TAs of 499kt.the IsA deviation at this level will be:
A. +17---------ans
B.+!9
C.-17
{i m getting my ans as +22degree plz help}
anS. 506hpa
plz Someone guide how to cal pressure change with altitude.
Q2.An inc. of 0.15Mach result in an inc. of 93kt TAs of an a/c. the local speed of sound is:
ANs-620KTs
PLZ guide how to solve this problem
Q3.An a/c is flying at 400ft from a high temp area to a cold temp area where the temp diff. is 20degree. what will be actual height of a/c:
Ans-3680feet
{As we are going from low density to high density area........the true height should decrease right!....i get that point but how to calculate barometric error......because QNH is not given....only temprature diff of 20degree is given.........plz explain}
Q4.An inc. of 0.15Mach number result in an inc. of93kts in TAs.if temp deviation from IsA Is +9DEGREE,the FL is:
ANs--FL220{plz explain}
Q5.The atmospheric pressure at FL70 in a "standard +10" atmosphere is:
ANs---781.85HPa{plz expalin}
Q6.Cruising at FL390,M0.84 is found to give a TAs of 499kt.the IsA deviation at this level will be:
A. +17---------ans
B.+!9
C.-17
{i m getting my ans as +22degree plz help}
Join Date: Jul 2011
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In the 6th question the temperature at FL 390 is -56.5 as the tropopause starts at 36090ft.
If you use this temp then the Isa dev will be +16 and very close to the answer.
In the first answer the pressure values are supposed to be mugged up.
eg 700hpa - 10000ft
800hpa - 18000ft
300hpa - 30000ft
200 hpa - 39000ft
The rest questions ill figure out and will let u know.
If you use this temp then the Isa dev will be +16 and very close to the answer.
In the first answer the pressure values are supposed to be mugged up.
eg 700hpa - 10000ft
800hpa - 18000ft
300hpa - 30000ft
200 hpa - 39000ft
The rest questions ill figure out and will let u know.
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@ AVIATORZ
Q1 There is a theoretical table of pressure at various altitudes. It goes like this,
850 HPa - 5000 Ft
700 HPa- 10000 Ft
500 HPa- 20000 Ft
300 HPa- 30000 Ft
200 HPa- 40000 Ft
50 HPa - 68000 Ft
The question states 18000 Ft, hence pressure would be just a little more than 500 HPa.
Q 2 Mach No.= TAS/LSS
Inc. of 0.15 mach = Inc of 93 kts TAS/LSS
LSS= 93/0.15= 620 Kts
Q4 LSS is same as above question, 620 kts
LSS= 38.94 sq.root of absolute temperature
Put in the value of LSS and absolute temp= 254 Kelvin= -19 degree C
Temperature Deviation= OAT- ISA temp.
+9 = -19-ISA
ISA Temp.= -28 Deg. C
ISA Temp= 15 - (2 X Altitude)
-28= 15- 2 X Alt.
Altitude= 21.5 = 21500 Feet (close to FL220)
Q6 M.No= TAS/LSS
Put in values of M.no and TAS and find out LSS which comes out to be 594 Kts.
LSS= 38.94 sq.root of absolute temp.
OAT=233 Kelvin= -40.27 deg. C
ISA temp. Above 36090 ft is -56.5 deg. c
OAT- ISA= Temp. Deviation
-40.27- (-56.5)= +16.23 deg C (Close to +17)
Q1 There is a theoretical table of pressure at various altitudes. It goes like this,
850 HPa - 5000 Ft
700 HPa- 10000 Ft
500 HPa- 20000 Ft
300 HPa- 30000 Ft
200 HPa- 40000 Ft
50 HPa - 68000 Ft
The question states 18000 Ft, hence pressure would be just a little more than 500 HPa.
Q 2 Mach No.= TAS/LSS
Inc. of 0.15 mach = Inc of 93 kts TAS/LSS
LSS= 93/0.15= 620 Kts
Q4 LSS is same as above question, 620 kts
LSS= 38.94 sq.root of absolute temperature
Put in the value of LSS and absolute temp= 254 Kelvin= -19 degree C
Temperature Deviation= OAT- ISA temp.
+9 = -19-ISA
ISA Temp.= -28 Deg. C
ISA Temp= 15 - (2 X Altitude)
-28= 15- 2 X Alt.
Altitude= 21.5 = 21500 Feet (close to FL220)
Q6 M.No= TAS/LSS
Put in values of M.no and TAS and find out LSS which comes out to be 594 Kts.
LSS= 38.94 sq.root of absolute temp.
OAT=233 Kelvin= -40.27 deg. C
ISA temp. Above 36090 ft is -56.5 deg. c
OAT- ISA= Temp. Deviation
-40.27- (-56.5)= +16.23 deg C (Close to +17)
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@SaabCapt
Stall Speed in a turn increases by 19% of initial at 45 degree bank.
19% of 100 is 19 Kts, so new speed would be 100 + 19= 119 Kts.
It is 7% for 30 deg bank
19% for 45 deg bank
41% for 60 deg Bank
100 % for 75 deg bank.
Stall Speed in a turn increases by 19% of initial at 45 degree bank.
19% of 100 is 19 Kts, so new speed would be 100 + 19= 119 Kts.
It is 7% for 30 deg bank
19% for 45 deg bank
41% for 60 deg Bank
100 % for 75 deg bank.
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Q2. LSS= TAS/M.No
93/.15 = 620
Irrespective of what your TAS or M.NO is the local speed of sound will be the same
Think of it as if you were flying at M.No 0.15 and with 93k as your TAS.
Q3.
I am assuming the question is for 4000 ft and not 400.
True altitude = P.A + (4*Height is thousands of feet* Temperature variation)
From the above mentioned formula for every 10deg rise in temp P.A increases by 4% or vice versa.
Since temperature variation is 20deg 8% of 4000 is 320.
And your flying from High Temperature to Low temperature hence your Altimeter will Over read. So its 4000-320 which is 3680.
Q.4
For the given figures LSS is 620(refer Q2).
To have a LSS of 620k the corresponding temp must be -20deg in ISA
Because it is Isa+9 we need to find an altitude that has a temp of -29 in ISA so that we can have -20deg at that altitude due to ISA deviation.
At FL220 ISA temp is -29
-29+9= -20.
LSS= 39*sq rt of(273-20)
LSS= 620.
Q.5
7000/30 = 233mb (1mb is 30 ft)
Standard + 10 = 233 +10 = 243
1013.2 -243 = 770 mb approx
I am not entirely sure of this particular solution, if anybody has a better way that would yield more accurate answer or if my answer is wrong, please shed some light I would like to learn it too.
And good luck with your preparations.!
93/.15 = 620
Irrespective of what your TAS or M.NO is the local speed of sound will be the same
Think of it as if you were flying at M.No 0.15 and with 93k as your TAS.
Q3.
I am assuming the question is for 4000 ft and not 400.
True altitude = P.A + (4*Height is thousands of feet* Temperature variation)
From the above mentioned formula for every 10deg rise in temp P.A increases by 4% or vice versa.
Since temperature variation is 20deg 8% of 4000 is 320.
And your flying from High Temperature to Low temperature hence your Altimeter will Over read. So its 4000-320 which is 3680.
Q.4
For the given figures LSS is 620(refer Q2).
To have a LSS of 620k the corresponding temp must be -20deg in ISA
Because it is Isa+9 we need to find an altitude that has a temp of -29 in ISA so that we can have -20deg at that altitude due to ISA deviation.
At FL220 ISA temp is -29
-29+9= -20.
LSS= 39*sq rt of(273-20)
LSS= 620.
Q.5
7000/30 = 233mb (1mb is 30 ft)
Standard + 10 = 233 +10 = 243
1013.2 -243 = 770 mb approx
I am not entirely sure of this particular solution, if anybody has a better way that would yield more accurate answer or if my answer is wrong, please shed some light I would like to learn it too.
And good luck with your preparations.!
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some one plz try to solve this problem as well
Q3.An a/c is flying at 400ft from a high temp area to a cold temp area where the temp diff. is 20degree. what will be actual height of a/c:
Ans-3680feet
{As we are going from low density to high density area........the true height should decrease right!....i get that point but how to calculate barometric error......because QNH is not given....only temprature diff of 20degree is given.........plz explain}
Ans-3680feet
{As we are going from low density to high density area........the true height should decrease right!....i get that point but how to calculate barometric error......because QNH is not given....only temprature diff of 20degree is given.........plz explain}
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load factor = 1/ cos(bank angle)
sq rt(loadfactor)* Vs = stall speed for any bank angle.!
1/cos45 = 1.414, sq rt(1.414) = 1.189.
Vs(45deg) = 1.189*100= 119.
Good Luck!
sq rt(loadfactor)* Vs = stall speed for any bank angle.!
1/cos45 = 1.414, sq rt(1.414) = 1.189.
Vs(45deg) = 1.189*100= 119.
Good Luck!
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There is simple formula for this..
Stall speed at the angle of bank = stall speed straight and level X underroot (1/ cos angle of bank)
You can calculate for any angle then..
so 100 X underoot 1/cos 45 = 119
Stall speed at the angle of bank = stall speed straight and level X underroot (1/ cos angle of bank)
You can calculate for any angle then..
so 100 X underoot 1/cos 45 = 119
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the question is wrong here..it should be 4000 ft,
When going from high temp to cold then it will over read..
and the reading changes 4degree per 1000 ft per degree C..
so 4 X 20 X 4 = 320 ft
over read means 4000- 320 = 3680ft
When going from high temp to cold then it will over read..
and the reading changes 4degree per 1000 ft per degree C..
so 4 X 20 X 4 = 320 ft
over read means 4000- 320 = 3680ft
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@SuperflyTNT It's werido not weirdo
in the step : " 4 X 20 X 4 = 320 ft "
First 4 is fts you use per thousand of altitude.
20 is the temperature difference.
second 4 is from the altitude which is 4000fts .
Hence it is 320 fts.
Rest is explained above by werido......
in the step : " 4 X 20 X 4 = 320 ft "
First 4 is fts you use per thousand of altitude.
20 is the temperature difference.
second 4 is from the altitude which is 4000fts .
Hence it is 320 fts.
Rest is explained above by werido......
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hi guys..
Q another name for " the leans " (H.F)
a.oculogravic effect
b.oculogyral illusion
c.somatogyral illusion
d.ocular disorientation
wat would be the right answer for this
as per me it shold be C but book says its B.
plz help...
a.oculogravic effect
b.oculogyral illusion
c.somatogyral illusion
d.ocular disorientation
wat would be the right answer for this
as per me it shold be C but book says its B.
plz help...
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@flyingmachine3
Vestibular/somatogyral illusions
Illusions involving the semicircular and somatogyral canals of the vestibular system of the ear occur primarily under conditions of unreliable or unavailable external visual references and result in false sensations of rotation. These include the leans, the graveyard spin and spiral, and the coriolis illusion.
Illusions involving the semicircular and somatogyral canals of the vestibular system of the ear occur primarily under conditions of unreliable or unavailable external visual references and result in false sensations of rotation. These include the leans, the graveyard spin and spiral, and the coriolis illusion.
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hi guys ...
any news from indigo about roll no. or hall tickets...
please could you mail mr. upendra nath email id to mail address [email protected].....
thank you.
any news from indigo about roll no. or hall tickets...
please could you mail mr. upendra nath email id to mail address [email protected].....
thank you.