Hey even i called up and they told me next attempt will be in November!!
Whom did you talk to?

@attitudeFlying & @mgrandhi: whom did both of you talk to????

Next attempt in November....2 to 3 days...between 10-20 November.
Confirm.

Oct 20 and 21st are the confirm dates i promise tht u can believe me blindly
just keep the studies up.

Dear fellow pilots of PPrune,

I have got my invite for the exam on 22nd.. I m sure that its the student who fault when they are not called. Reckon this, 2 of my friends have got expired IR on their multi and were sitting with their fingers crossed in order to get their invite.. They dont get it.. I will talk to Sandra or RAdhika whoever is present to the venue tomoro.. n post whether the next exam is in October or November..

Happy Landings every1:O:O:)

@Transponder777

I have Two friends who's multi IR expired in August 2011......

Both of them got called for tomorrows exam.

@ to all.....PLZ do try to give the answers as well.......
thanks in advance......
and dont get disheartened as you are jst getting extra time for prep...
as preparation is never complete and alot is always there to learn......

ALSO, its not reqd to have a valid multi IR for Indigo exam but one should have endorsed....

Friends kindly
, post the questions those who have appeared on. 21 sept ie todays exam .it would be of great help for all of us .

Q1 An a/c is desccending a 12% slope at a GS of 540 kt. what is the rate of descent?
A 4500fpm
B 3900fpm
C 6500fpm
D 650fpm

Q2 wpt 1 60S 30W
wpt 2 60S 20W
What will be the apprx lattitude shown on a display of an INS at longitude 25W
ANS 60degrees6min S

Having a bit of trouble with this. I would appreciate anybody trying to explain these questions. cheers.

@thearsenal

Explanation to Q1:

The % slope is the tan of the slope angle * 100%.
So, in a 12% glideslope. tan of the slope angle is 12/100 = 0.12.
This gives a slope angle of 6.843deg.

But the tangent of the slope = ROD/Groundspeed
Therefore, ROD = tan slope * groundspeed which gives
ROD = 0.12 * 540KTS = 64.8KTS
Converting 64.8kts in fpm (MULTIPLY IT BY 101.33, SINCE, 1KT = 101.33ft/min)

ROD = 6564.24 ft/min

Option c) is closest to this answer.

At medium lat, Coriolis Force experienced is:
a. 7.5 deg to the right
b. 15 deg to the left
c. 7.5 deg to the left
d. 10.5 deg to the right

The question doesn't mention the hemisphere. Could anyone pls explain this?

@ aviator ( done it well) and the arsenal
ques 1
descending with a 12% slope means a/c loses 12% of ht per nm
i.e 12% 0f 6080 feet = 729.6 feet

so for 540 kts => 540 nm/hr =>
540/60 = 9nm/min
and 12% of 9nm => (9/100)*12 = 1.08nm or 1.08 * 6080 = 6566.4 feet
approx to 6500

exam on 21th sept 2011
 

people who appeared today-
Q1 How was the exam??
Q2 How many appeared??
Q3 How many made it to the next round??
Q4 Was the exam on the same pattern ie. 100 questions, same topics??
Q5 Any idea when the next attempt is going to be??

Guys I appeared for the exam today.

exam pattern was pretty much the same lots of questions on human
performance, ifr procedures, few air regs questions, 2-3 cdmvt questions, few met questions (clouds at mid level/low level), feq qff qfe qnh questions , 5-6 questions on a/c intercepted by other aircraft procedures, 5-10 questions came from the question bank earlier posted in this thread.....

Rest will update later....

Total 52 people appeared out of which 14 cleared.....

@adi

Hi

I am not familiar with the term cdmvt

Could you expand the term for me please :O

cyril Roy.
 

Its a synonym used to find out the compass or magnetic or true heading whatever has been asked in the question.

C- Compass heading
D- Deviation E/W
M- Magnetic Heading
V- Variation E/W
T- True Heading.

Add or subtract acc. to East least West Best rule and you can find the answer directly..

all the best for tomoro..

:O:)

C D M V T is an acronym used for compass, deviation, magnetic, variation and true.
For the ease of remembering the order its known as,
Chocolate Delhi Milk Very Tasty! Can Ducks Make Vertical Turns! Can Dead Men Vote Twice! when doing conversions from compass to true.

Vice-Versa from true to compass its known as True Virgins Make Dull Company!

You should have come across this for your DGCA Nav papers.

Given below is a link with a pictorial representation for a quick look.

http://www.wetpaper.com.au/products/...dfs/P42Nav.pdf

Thanks guys

Yes i did come across such question relating to such questions during the nav exams .

I have a manual E6B on which the formula to convert is printed on it and hence always used that to solve such problems

PPRuNe is the first place that i heard use this particular acronym

Anyway thanks once again

Any idea how long it took for them to announce the results today ?

request
 

Guys congrates those who manage to get to second stage...:D
I am planning to write next attempt if i will get the call..
So, its a genuine request please make some efforts like previous member did and give brief details of the paper like subject wise numbers ( total to 100) , topic covered, any new topic they added , and still no technical(engine, airframe and systems etc.)....:D
thanks in advance
ala

Came across this question in Oxford-Radio Nav, bit confused about the correct answer.

An accuracy of +/-5deg in VOR bearings received at an a/c is achieved:
a) within the cone of confusion by day only
b) at all ranges within the DOC limits day & night
c) within the DOC limits by day only
d) beyond the cone of confusion as far as the DOC limits by day and night.

Pls help me out with this one.