@flying machine
 

The answer is a.

A cambered aerofoil produces lift even at 0 angles of attack. On a typical cambered aerofoil, -4 degs produces 0 lift. And since there is lift at 0 degrees, there is induced drag too.

Quick question for those who have applied for the program and got a call for the exam. I applied on the 21st of September for the Indigo-Cae program but did not get a call for this exam.

How long after you guys applied did you get the first call for the exam?

I got a call for the exam on the 20th:D

@superdrunker
 

it really depends. coz its just a computer generated call

vmendes
 

thanks mate

Just trying to figure out what the average is.

guys can u plz help
 

On a Lambert conformal chart the distance between two parallels of latitude having a difference of latitude = 2° , is measured to be 112 millimetres. The distance between two meridians, spaced 2° longitude, is, according to the chart 70 NM. What is the scale of the chart, in the middle of the square described?
A) 1 : 1 056 000
B) 1 : 756 000
C) 1 : 1 984 000
D) 1 : 1 233 000
ans c
how exactly thats has come could you please tell me

Flying machine
 

Why don't you put up your questions in the 'General Navigation questions' thread ? In that way, it is much easier for others to track all the questions as well. :ok:

bieng human
 

i am sorry but i am not aware of that thread can please tell me the link aswell
thanks

Hall Ticket?
 

Hey I got second mail on 14 oct. but didnt get hall ticket:(
Any one else in the same situation waiting for final mail:ugh:
Please reply
ala

Help!!
 

A pilot receives the following signals from a VOR DME station: radial 180° +/- 1° , distance = 200 NM. What is the approximate error?
A) +/- 3.5 NM. [correct answer]

B) +/- 7 NM.

C) +/- 2 NM.

D) +/- 1 NM.

mine comes out to be 2.5nm

Use 1 in 60 rule and use degree as 1

200/60 = 3.33 ~ 3.5

has anyone received the hall ticket for 21st oct apart from DJ flyboy???

climb ... due to the inversion which means warmer air is present above.

I think it is 150..since there is no wind mentioned we cant factor it in.

To the guys who did not get a call do not worry there will be atleast one more exam if not two before the end of this year.

They had one A/C delivered on the 11th of this month and still 3 more to come by end of this year.

So keep studying hard and be patient!
:)

@liedetector
 

Indigo is gonna conduct exam every month for sure. Next assessment is on nov 3rd week. dates not fixed yet

hey guys, all the best for tomorrow.:)

Please help solve this question...
The center of a small island is identified at the intersection of 60 degree left bearing line and 15nm range arc of airborne weather radar. If aircraft's heading and height are 035 degrees (M) and 42500 feet. What QTE and range should be plotted in order to obtain a fix from the island? Var - 20W.

Ans - 135 degrees and 13nm.

035(m)-60 =335 (m)
Var = 20w therefore True bearing is 315
QTE = 315-180=135

42500feet = 7nm
Use Pythag Distance = sqrt(15x15 - 7 x 7) =13.26 nm