Indigo Call letters for Freshers
Join Date: Apr 2011
Location: Mumbai
Age: 34
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How different from Jet??
I cleared the Aug jet airways written, but not the group discussion 
I want to know how different is this from jet?? ive heard this is way harder, is that true??
I want to know how different is this from jet?? ive heard this is way harder, is that true??
Join Date: Aug 2010
Location: Delhi
Age: 34
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what is the rhumb line track from A (4500N 01000W) to B (4830N 01500W) ?
Thats all the info provided in the question
can't seem to get my head around it?
please post the complete answer with method.
Thanks!
Thats all the info provided in the question
can't seem to get my head around it?
please post the complete answer with method.
Thanks!
Join Date: Mar 2011
Location: India
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@livetokill
Have you got the answer for the question...
If my method is right then the answer might be close to 313. I'll explain it further if its right.
Expecting a reply... thanks...
Have you got the answer for the question...
If my method is right then the answer might be close to 313. I'll explain it further if its right.
Expecting a reply... thanks...
Last edited by airtransporter; 21st Apr 2011 at 11:15.
Join Date: Mar 2011
Location: India
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what is the rhumb line track from A (4500N 01000W) to B (4830N 01500W) ?
Answer:
Let’s assume an imaginary point X on (4830N 01000W)
[Draw a diagram for your reference]
Now the coordinates of A and B with point X form a right angle triangle (straight line AB will be a great circle path, AB being the hypotenuse)
Find distances AX and XB using distance and departure formula.
You’ll get AX = 210nm and XB = 198.
Now further you can calculate angle BAX using trigonometry tangent formula. This comes to around 43.5 degrees. The direction of line AB is true north (360)
So, we get the great circle track of 317.
(din't apply CA properly when I calculated it first)
After applying conversion angle (2 degrees) the rhumb line track will be 315.
Let’s assume an imaginary point X on (4830N 01000W)
[Draw a diagram for your reference]
Now the coordinates of A and B with point X form a right angle triangle (straight line AB will be a great circle path, AB being the hypotenuse)
Find distances AX and XB using distance and departure formula.
You’ll get AX = 210nm and XB = 198.
Now further you can calculate angle BAX using trigonometry tangent formula. This comes to around 43.5 degrees. The direction of line AB is true north (360)
So, we get the great circle track of 317.
(din't apply CA properly when I calculated it first)
After applying conversion angle (2 degrees) the rhumb line track will be 315.
Join Date: Jan 2011
Location: india
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the exam is happening on the 25th and 26th only. not enough applicants to have it over 5 days