guyz can u plz help me these ques
 

An aircraft is flying at FL 140 where the COAT is -5° C. It is flying at an indicated air speed of 260 kts and is experiencing a headwind of 34 knots. When 150 nm from the FIR boundary it is instructed to reduce speed in order to delay arrival at the boundary by 5 minutes. The required reduction in indicated air speed is:
A) 33 kts.
B) 41 kts.
C) 24 kts.
D) 15 kts.
ans a
The time interval between the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the aircraft is 2 milli seconds. The slant range is:
A) 162 nm
B) 73 nm
C) 323 nm
D) 92 nm

ans is 162nm

IAS or CAS = 260 kts Find TAS which = 323 kts wind = 34 Headwind therefore Ground speed = 289 kts , Now time taken to cover 150Nm @ 289 = 31min.wit a delay of 5 min revised time = 36 min . Now speed = Distance/ Time therefore Speed @ delay of 5min= 150/36 min = 250 kts (ground speed) now convert 250 kts to TAS by adding 34 kts headwind which give you TAS of 284 kts using your flight computer Find CAS @ that TAS which equates to 228 kts ,,,,

now find the difference : 260 Kts -228Kts = 32 kts / 33kts :rolleyes:

An aircraft is flying at FL 140 where the COAT is -5° C. It is flying at an indicated air speed of 260 kts and is experiencing a headwind of 34 knots. When 150 nm from the FIR boundary it is instructed to reduce speed in order to delay arrival at the boundary by 5 minutes. The required reduction in indicated air speed is:
A) 33 kts.
B) 41 kts.
C) 24 kts.
D) 15 kts.
ans a
The time interval between the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the aircraft is 2 milli seconds. The slant range is:
A) 162 nm
B) 73 nm
C) 323 nm
D) 92 nm

ans is 162nm


the first one seems dodgy but colsest i came was using cx2 using actual tas and a CAS of 226 ...i got an ans of 36 kts difference

2nd one is simple

distance = speed/time = 3*10^8 / 0.002 = 324
but this equals distance wave travels to stn and back so we divide by 2 we get 162

Maverick2167
 

thanks for the help bro

Shabez
 

thanks for the help

CONTACT NUMBER FOR CAE PEOPLE
 

Hii friends i have been trying to get a hall number for indigo assessment for pretty long time now ..can sum1 plz PM the contacts number for the cae people

any info will be appreciated

Where are all the above questions found exactly??

just received my hall ticket e-mail from Capt Upendranath for the 20th Oct..

Butterfly whats the venue this time..

same as earlier..that "parkland hotel"..wish they'd found a better place!!

Thanks buddy!

edit: Just got my hall ticket..for 21st

help needed

Whats the formula to calculate NDB range??

The nominal maximum range of an NDB with a transmitter power is 200 watts is:

A) 150 to 170 nm.
B) 200 to 220 nm.
C) 100 to 120 nm.
D) 50 to 60 nm.

the formula for NDB range is
over water (nm) = 3√Wattage
Over Land (nm) = 2√Wattage

So according to me the range of a 200 W NDB is 2√200 =28.3nm

is the answer in Km or nm??

nms i suppose!!
none of the ans match with these formulae?!?!?!?
another Q

The approximate range of a 10 KW NDB over the sea is:

A)100 nm

It must be 1KW
Range over water = 3√1000 =94.8 =approx 100nm
where are you getting these questions from?

aviationtire..where r u studying from??

though many of their qs do contradict each other!!

Just the books.
i dont think all their answers are correct

help please..

An aircraft is over flying a VOR at 30.000 ft, at a groundspeed of 300 kt. The maximum time during which no usable signals will be received (in minutes and seconds) is:

A)0.50
B)4.40
C)2.25
D)1:40

guys can u plz help
 

A cambered airfoil with zero angle of attack, will in flight produce:
A) some lift and some drag.
B) no lift and no drag
C) some lift with no drag.
D) no lift but some drag.

@ buttefly747
 

it has been answerd 4 days ago

http://www.pprune.org/south-asia-far...questions.html