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Old 21st April 2011 | 06:48
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From: india
Question Help with this Question

An aircraft takes off from an airport 2 hrs before sunset . The pilot flies a track of 90 T , W/V 130/20 , TAS 100kts . In order to return to the point of departure before sunset , furthest distance which maybe traveled is :

a. 84 nm
b. 97 nm
c. 105 nm
d. 111 nm

somehow i am not able to figure out a way to approach this quest any help will be appreciated .

Thanks
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Old 21st April 2011 | 07:30
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From: Underground
Try the PNR formula...should work
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Old 21st April 2011 | 08:45
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Why dint i see that one coming

thanks for the help
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Old 21st April 2011 | 08:48
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From: Up in the air
Doesn´t matter if it is time to sunset or time to running out of fuel...

Distance to Point of No Return =
(Fuel endurance (hours) × Ground speed return (knots) × Groundspeed outbound (knots)) / (Ground speed return (knots) + Groundspeed outbound (knots))

Correct answer: 97 nm
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Old 21st April 2011 | 09:03
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From: Ex-pat Aussie in the UK
Given the time needed to accelerate to cruise TAS, to turn around and to decelerate and fly a circuit/an approach - the answer is probably 84nm
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Old 21st April 2011 | 10:25
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From: up high
it is assumed that the a/c does nor do all of those thing when questions like these are made....correct ans 97...
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Old 21st April 2011 | 11:01
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From: india
yes the correct answer in 97 kts
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Old 21st April 2011 | 11:38
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From: Underground
No probs Best of luck for the exam...
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