![]() |
Help with this Question
An aircraft takes off from an airport 2 hrs before sunset . The pilot flies a track of 90 T , W/V 130/20 , TAS 100kts . In order to return to the point of departure before sunset , furthest distance which maybe traveled is :
a. 84 nm b. 97 nm c. 105 nm d. 111 nm somehow i am not able to figure out a way to approach this quest any help will be appreciated . Thanks |
Try the PNR formula...should work :ok:
|
Why dint i see that one coming :( :ugh:
thanks for the help :ok: |
Doesn´t matter if it is time to sunset or time to running out of fuel...
Distance to Point of No Return = (Fuel endurance (hours) × Ground speed return (knots) × Groundspeed outbound (knots)) / (Ground speed return (knots) + Groundspeed outbound (knots)) Correct answer: 97 nm |
Given the time needed to accelerate to cruise TAS, to turn around and to decelerate and fly a circuit/an approach - the answer is probably 84nm ;)
|
it is assumed that the a/c does nor do all of those thing when questions like these are made:sad:....correct ans 97...:ok:
|
yes the correct answer in 97 kts
|
No probs :) Best of luck for the exam...:ok:
|
| All times are GMT. The time now is 10:43. |
Copyright © 2026 MH Sub I, LLC dba Internet Brands. All rights reserved. Use of this site indicates your consent to the Terms of Use.