How can you work out height loss relative to your starting position?
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How can you work out height loss relative to your starting position?
This is an obscure question so it's only out of curiousity I ask:
How can you work out how much distance you travel towards a position directly below you as you move around a circle?
So for example, if you move from A to B and B is one quarter of the way around the earth, for example, you travel 5400 nm great circle and you move vertically downwards by 3437.74 nm (or one radius of the earth). In other words you could travel directly down to the center of the earth at point A and then travel forward towards B and you'd end up at B (vertical) having travelled 3437.74 nm "down".
Does the question make any sense?
Thanks for any replies,
Screwballs (who needs to get out more)
How can you work out how much distance you travel towards a position directly below you as you move around a circle?
So for example, if you move from A to B and B is one quarter of the way around the earth, for example, you travel 5400 nm great circle and you move vertically downwards by 3437.74 nm (or one radius of the earth). In other words you could travel directly down to the center of the earth at point A and then travel forward towards B and you'd end up at B (vertical) having travelled 3437.74 nm "down".
Does the question make any sense?
Thanks for any replies,
Screwballs (who needs to get out more)
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If you're asking what I think you are, whcih is basically how do you work out the circumference of a circle, it'll be Pi multiplied by the twice the radius of the circle. In your exaple your asking for quater of the circumference so it'd be:
(Pi x 2r)/4
(3.14159 x 2 x 3437.74)/4 = 5399.989
Or you could be asking a different question, in which case I don't have a clue what you're on about.
(Pi x 2r)/4
(3.14159 x 2 x 3437.74)/4 = 5399.989
Or you could be asking a different question, in which case I don't have a clue what you're on about.

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Does the question make any sense?
However, in an effort to answer the question which I believe you were trying to ask, your 'height loss' or 'vertical distance' is given by this cunning formula, which I have devised especially for you on your journey to the centre of the Earth:
'height loss' = 3438NM x (1 - COSINE ('distance travelled' / 60)), which works for any distance travelled, whether part way round the Earth, completely round it, and even going around it as many times as you care to go round in circles.
The above formula assumed Degrees in the COSINE function. If you need to use Radians on your unbelieveably bizarre journey, then the following formula may be used:
'height loss' = 3438NM x (1 - COSINE ('distance travelled' / 3438))
Now, by return, would you kindly answer for me, what relevance this is to anyone, for any purpose whatsoever, please??!!!
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How can you work out how much distance you travel towards a position directly below you as you move around a circle?
Does this answer your question? Sorry, but the phrasing in your original post was a bit vague so I'm just having a best guess at what you were trying to ask.
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This is an obscure question so it's only out of curiousity I ask:
Thanks pilotmike for the formula, it was just idle curiosity and I couldn't work one out myself!
Screwballs
Warning Toxic!
Disgusted of Tunbridge
Disgusted of Tunbridge
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No it doesn't actually. It's such an obscure, nonsensical question with no logic I read it several times and still could not understand it! I am surprised anybody answered it! So, no, your first line does not actually provide an exoneration! I think my first wife has similar confused thought processes.
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From: In your head.
How can you work out height loss relative to your starting position?
Answer - Subtract your finishing position from your starting position.
How can you work out how much distance you travel towards a position directly below you as you move around a circle?
Answer - Spherical trigonometry - Wikipedia, the free encyclopedia
Answer - Subtract your finishing position from your starting position.
How can you work out how much distance you travel towards a position directly below you as you move around a circle?
Answer - Spherical trigonometry - Wikipedia, the free encyclopedia

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From: UK
No, Screwballs, Rainboe is completely right. It really was a truly hairbrained question, and worded in such poor layman's terms, that I found it hard to believe that you are indeed a pilot.
Just because Rainboe points this out shouldn't cause you to get your knickers in a twist with him!
Just because Rainboe points this out shouldn't cause you to get your knickers in a twist with him!
Thread Starter
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Ah come now, not got the knickers in a twist, just trying to wind him up as he does to everyone else.
I thought there was no such thing as a stupid question but I guess I was wrong. Better stop asking anymore questions then!
Thanks for the answer all the same.
Screwballs
I thought there was no such thing as a stupid question but I guess I was wrong. Better stop asking anymore questions then!
Thanks for the answer all the same.
Screwballs

Joined: Nov 2004
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From: UK
No sweat, Screwballs! I never meant to have a pop at you, I just had to slip 'knickers' into a post to win a £20 bet - honestly!
For my next £20, - 'dehumidifier'.
There, I've now earned 40 quid in just 20 minutes, and I haven't even gone out to work yet, I report in 3 hours time.
For my next £20, - 'dehumidifier'.
There, I've now earned 40 quid in just 20 minutes, and I haven't even gone out to work yet, I report in 3 hours time.

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LOL Screwballs – interesting question - with some merit (and controversy) too! My 0.5 penny’s worth! Not quite sure (as a simple bloke) where your “..around the earth” dit comes from – but, as a some-time simple glidist, I often have to work a similar question out for real - when looking for a rescue-thermal to save my bacon. My question in a dying thermal is “How long have I got before I have to commit to a ‘Downwind to a field landing’ decision?”
The simple answer I apply is ((Current height agl (estimated from topography) – 800ft agl)/ROD (ft/min)) = time left before I have to give it up and head for the sheep/cow/barley field! I know (roughly) how many RPM I am doing so I could work out how many orbits I could make. So, in theory, you could multiply TAS (GS should even out as constantly flying “into” and “out of” wind) by the time to “downwind decision point” or “crash site” to give a distance travelled to either event!
But, practically, I just work on a closest cut-off altitude to a downwind leg. When I reach that – "Hello sheep/cows/barley"!!!!! As for distance travelled? Mmmm, don’t care really as a pilot – but, using a formula for a conical spiral (or my calculation above), I guess you could work it out if aiming at a particular sheep within said field! However, in practical terms – neither I nor the sheep would be worried – provided (from both sides) I missed the sheep on flare/roll-out!!!!
Hope this is of mild curious interest! If not – my apologies! Ho hum!!!
H 'n' H
The simple answer I apply is ((Current height agl (estimated from topography) – 800ft agl)/ROD (ft/min)) = time left before I have to give it up and head for the sheep/cow/barley field! I know (roughly) how many RPM I am doing so I could work out how many orbits I could make. So, in theory, you could multiply TAS (GS should even out as constantly flying “into” and “out of” wind) by the time to “downwind decision point” or “crash site” to give a distance travelled to either event!
But, practically, I just work on a closest cut-off altitude to a downwind leg. When I reach that – "Hello sheep/cows/barley"!!!!! As for distance travelled? Mmmm, don’t care really as a pilot – but, using a formula for a conical spiral (or my calculation above), I guess you could work it out if aiming at a particular sheep within said field! However, in practical terms – neither I nor the sheep would be worried – provided (from both sides) I missed the sheep on flare/roll-out!!!!
Hope this is of mild curious interest! If not – my apologies! Ho hum!!!
H 'n' H
Last edited by Hot 'n' High; 15th January 2009 at 19:34.





