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Another load factor question

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Old 30th June 2006 | 22:00
  #1 (permalink)  
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From: Toronto, Ont, Canada
Another load factor question

Crusing S&L in your spamcan @ 100kts.

Some abrupt backpressure and one second later you've gained ~60 feet.

Is that ~2g's ? (9.8 m/s /s (~30ft/sec/sec))

If so, if you gained 90 feet after 2 seconds, would that also be 2g's ?

Mike
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Old 30th June 2006 | 22:08
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Per Ardua ad Astraeus
 
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From: UK
s=1/2 at^2

60 = 1/2 x a x 1^2

a=120 / 1

a=120 fpsps

a=4g (probably broken spamcan )

After 2 seconds,

a= 180 / 4

a=45 fpsps

a=1.5 g

Bedtime now!
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Old 30th June 2006 | 23:53
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From: Toronto, Ont, Canada
Originally Posted by BOAC
s=1/2 at^2

60 = 1/2 x a x 1^2

a=120 / 1
a=120 fpsps
a=4g (probably broken spamcan )
After 2 seconds,
a= 180 / 4
a=45 fpsps
a=1.5 g
Bedtime now!
LOL !
Do you also program with APL ?
Any time you feel like adding a few lines of english explanation, that would be great
Mike

Last edited by mstram; 1st July 2006 at 00:21.
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Old 1st July 2006 | 03:39
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Joined: Sep 2002
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From: La Belle Province
unless you end up still doing S&L flight, some of the height gain comes not from pure vertical accel but from changing the direction of flight.

You can climb at several thousand fpm with less than 1'g', if the flightpath vector points up enough.

cant be bothered working out the physics right now, though ... too many bevvies
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Old 1st July 2006 | 04:19
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From: Nirvana South
Originally Posted by Mad (Flt) Scientist
cant be bothered working out the physics right now, though ... too many bevvies
Happy Canada Day, MFS!
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Old 1st July 2006 | 08:08
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From: UK
Apologies, mstram, I assumed you had a basic grasp of physics

From Google: http://www.physchem.co.za/Graphs/Equations.htm

Greetings to the colonies
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