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Another load factor question
Crusing S&L in your spamcan @ 100kts.
Some abrupt backpressure and one second later you've gained ~60 feet. Is that ~2g's ? (9.8 m/s /s (~30ft/sec/sec)) If so, if you gained 90 feet after 2 seconds, would that also be 2g's ? Mike |
s=1/2 at^2
60 = 1/2 x a x 1^2 a=120 / 1 a=120 fpsps a=4g (probably broken spamcan :) ) After 2 seconds, a= 180 / 4 a=45 fpsps a=1.5 g Bedtime now! |
Originally Posted by BOAC
s=1/2 at^2
60 = 1/2 x a x 1^2 a=120 / 1 a=120 fpsps a=4g (probably broken spamcan :) ) After 2 seconds, a= 180 / 4 a=45 fpsps a=1.5 g Bedtime now! Do you also program with APL ?:ooh: Any time you feel like adding a few lines of english explanation, that would be great :ok: Mike |
unless you end up still doing S&L flight, some of the height gain comes not from pure vertical accel but from changing the direction of flight.
You can climb at several thousand fpm with less than 1'g', if the flightpath vector points up enough. cant be bothered working out the physics right now, though ... too many bevvies :) |
Originally Posted by Mad (Flt) Scientist
cant be bothered working out the physics right now, though ... too many bevvies :)
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Apologies, mstram, I assumed you had a basic grasp of physics:)
From Google: http://www.physchem.co.za/Graphs/Equations.htm Greetings to the colonies:) |
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