Indigo Call letters for Freshers
Join Date: Jan 2011
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human factors doubt
hello friends,
i have on doubt regarding the respiration process at higher altitude....
as at sea level our partial pressure of oxygen is 160mm of hg but in the alveolar air partial pressure of oxygen is 103 mm of hg....
but at 10,000 feet partial pressure of oxygen is 55mm of hg..
so as we go higher and higher say above 40,000 feet we need to 100%oxygen under pressure ..............but by doing this are we maintaining partial pressure of oxygen to that of sea level partial pressure or to that of 10,000 feet partial pressure of oxygen.?
thanks for the support frends
i have on doubt regarding the respiration process at higher altitude....
as at sea level our partial pressure of oxygen is 160mm of hg but in the alveolar air partial pressure of oxygen is 103 mm of hg....
but at 10,000 feet partial pressure of oxygen is 55mm of hg..
so as we go higher and higher say above 40,000 feet we need to 100%oxygen under pressure ..............but by doing this are we maintaining partial pressure of oxygen to that of sea level partial pressure or to that of 10,000 feet partial pressure of oxygen.?
thanks for the support frends
Join Date: Aug 2010
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1) A/c at same configuration and weight takes off at same-EAS or CAS?
2)VSI is fed by- Differential pressure or static pressure?
and for Altimeter its static pressure
Join Date: Mar 2011
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Urgent help required !
I dont know if I'm the only one who made this frivolous discovery on the CX2 but its been bugging me ever since!
HAS anybody had any problem calculating Headwind/tailwind & crosswind components and tallying the answers with the ones using actual fromula ?
HWC/TWC = windspeed x Cos Xdeg,
CWC= windspeed x Sin Xdeg. ( for those who didn't know!)
say for eg. Hdg= 30 deg, W/V = 60/30.
solve this using the formula and CX2, ANSWER DOESN'T MATCH!
COULD ANYBODY PLEASE OFFER A VALUABLE SOLUTION ?
Join Date: Dec 2010
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rule of thumb for calculating climb or descend gradient :
ROC or ROD / Groundspeed = X %
in your example : TAS can be assumed as Groundspeed ,
hence 1000fpm/ 194 kts = 5.15 % or 3 degrees ( ANSWER!)
...can anybody please solve Cloudripper's query , strange but I've never realised it until now too!
ROC or ROD / Groundspeed = X %
in your example : TAS can be assumed as Groundspeed ,
hence 1000fpm/ 194 kts = 5.15 % or 3 degrees ( ANSWER!)
...can anybody please solve Cloudripper's query , strange but I've never realised it until now too!
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@Aviator4u,
Use Trigonometry mate.
Convert 194kts, into ft/min. That would be your adjacent side.
a vertical speed of 1000 ft/min would be your opposite.
tan (climb angle) = 1000/194 x 6080/60
apply tan inverse, to get the answer of 2.92 degrees, round it off to 3.
Use Trigonometry mate.
Convert 194kts, into ft/min. That would be your adjacent side.
a vertical speed of 1000 ft/min would be your opposite.
tan (climb angle) = 1000/194 x 6080/60
apply tan inverse, to get the answer of 2.92 degrees, round it off to 3.
Join Date: Jun 2011
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@climb gradient
climb gradient = (rate of climb * 6000)/ (tas*6080)
GLIDE PATH (DEGREES) = ((GLIDE PATH (%)*60))/100
CLIMB GRAD = (1000*6000)/(194*6080) = 5.08
GP(DEG) = (5.08 * 60 )/100 = 3 DEGREES
GLIDE PATH (DEGREES) = ((GLIDE PATH (%)*60))/100
CLIMB GRAD = (1000*6000)/(194*6080) = 5.08
GP(DEG) = (5.08 * 60 )/100 = 3 DEGREES
Join Date: May 2008
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@ cloud ripper
The concept here apply's of VELOCITY TRAIANGLE
1. True wind component
2. Effective wind component
In true wind component Along track and across track components co-exists and hence the formula of cos and sin gives the right ans.
However, when we talk about HWC and TWC Effective wind components come into the picture.
acc to which GS-TAS= wind component
this wind component if Neg implies a HWC and if Pos implies TWC.
Now this VALUE of the wind component can be diff for calculating HWC and TWC.
In this picture it is shown that how effective wind components often differ.
The TAS is acting along the heading but the effect of the TAS along the track will be TAS cos drift. TAS cos of drift is less the TAS . To get the GS the true component will have to be applied to this.
Hence the difference between the true n effective wind component is TAS- TAS cos drift.
Hence Effective wind component is always less favourable unless there is no drift, ie, in flying directly UPwind and downwind.
1. True wind component
2. Effective wind component
In true wind component Along track and across track components co-exists and hence the formula of cos and sin gives the right ans.
However, when we talk about HWC and TWC Effective wind components come into the picture.
acc to which GS-TAS= wind component
this wind component if Neg implies a HWC and if Pos implies TWC.
Now this VALUE of the wind component can be diff for calculating HWC and TWC.
In this picture it is shown that how effective wind components often differ.
The TAS is acting along the heading but the effect of the TAS along the track will be TAS cos drift. TAS cos of drift is less the TAS . To get the GS the true component will have to be applied to this.
Hence the difference between the true n effective wind component is TAS- TAS cos drift.
Hence Effective wind component is always less favourable unless there is no drift, ie, in flying directly UPwind and downwind.
Join Date: May 2008
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The information is from GSP Navigation.
If these questions asked or not i do not know but it depends how the question is framed. Generally a simple theory question will be asked if "if asked".
If these questions asked or not i do not know but it depends how the question is framed. Generally a simple theory question will be asked if "if asked".
Join Date: Nov 2010
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@harsh786techy-
Thank you for you reply,but acc to your formula range in the case of 10 KW should be 3*SQRT(10000) which works out to be 300 NM and it is nowhere close to the answer options which are-50NM,100NM,500NM,1000NM
Thank you for you reply,but acc to your formula range in the case of 10 KW should be 3*SQRT(10000) which works out to be 300 NM and it is nowhere close to the answer options which are-50NM,100NM,500NM,1000NM
Join Date: May 2008
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The answer to be marked for this ques should be 100. for solving such problems simply square root of wattage is considered.
However for the comparison the factors of 2 and 3 are considered. i am sure the ans must be 100. if its not then i will look into it.
However for the comparison the factors of 2 and 3 are considered. i am sure the ans must be 100. if its not then i will look into it.