Indigo Call letters for Freshers
Join Date: Jul 2011
Location: India
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@flying machine
The answer is a.
A cambered aerofoil produces lift even at 0 angles of attack. On a typical cambered aerofoil, -4 degs produces 0 lift. And since there is lift at 0 degrees, there is induced drag too.
A cambered aerofoil produces lift even at 0 angles of attack. On a typical cambered aerofoil, -4 degs produces 0 lift. And since there is lift at 0 degrees, there is induced drag too.
Join Date: May 2010
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Quick question for those who have applied for the program and got a call for the exam. I applied on the 21st of September for the Indigo-Cae program but did not get a call for this exam.
How long after you guys applied did you get the first call for the exam?
How long after you guys applied did you get the first call for the exam?
Join Date: Mar 2011
Location: asia
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guys can u plz help
On a Lambert conformal chart the distance between two parallels of latitude having a difference of latitude = 2° , is measured to be 112 millimetres. The distance between two meridians, spaced 2° longitude, is, according to the chart 70 NM. What is the scale of the chart, in the middle of the square described?
A) 1 : 1 056 000
B) 1 : 756 000
C) 1 : 1 984 000
D) 1 : 1 233 000
ans c
how exactly thats has come could you please tell me
A) 1 : 1 056 000
B) 1 : 756 000
C) 1 : 1 984 000
D) 1 : 1 233 000
ans c
how exactly thats has come could you please tell me
Join Date: Jul 2011
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Flying machine
Why don't you put up your questions in the 'General Navigation questions' thread ? In that way, it is much easier for others to track all the questions as well. 
Hall Ticket?
Join Date: Aug 2011
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Help!!
A pilot receives the following signals from a VOR DME station: radial 180° +/- 1° , distance = 200 NM. What is the approximate error?
A) +/- 3.5 NM. [correct answer]
B) +/- 7 NM.
C) +/- 2 NM.
D) +/- 1 NM.
mine comes out to be 2.5nm
A) +/- 3.5 NM. [correct answer]
B) +/- 7 NM.
C) +/- 2 NM.
D) +/- 1 NM.
mine comes out to be 2.5nm
Join Date: Jan 2010
Location: India
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An aircraft heading 130° (M) has an ADF reading of 190° Relative is to intercept the 170° (M) track outbound from an NDB at 30° . The relative bearing of the NDB that confirms track interception is:
A) 150° Relative.
B) 140° Relative.
C) 160° Relative.
D) 170° Relative
i get answer as 150 but it is listed as 140 in the question bank...
if i consider it as wind then it should give me 160 relative
A) 150° Relative.
B) 140° Relative.
C) 160° Relative.
D) 170° Relative
i get answer as 150 but it is listed as 140 in the question bank...
if i consider it as wind then it should give me 160 relative
Join Date: Jun 2011
Location: LieDetector
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To the guys who did not get a call do not worry there will be atleast one more exam if not two before the end of this year.
They had one A/C delivered on the 11th of this month and still 3 more to come by end of this year.
So keep studying hard and be patient!
They had one A/C delivered on the 11th of this month and still 3 more to come by end of this year.
So keep studying hard and be patient!
Last edited by LieDetector; 18th Oct 2011 at 17:01.
Join Date: Oct 2011
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Please help solve this question...
The center of a small island is identified at the intersection of 60 degree left bearing line and 15nm range arc of airborne weather radar. If aircraft's heading and height are 035 degrees (M) and 42500 feet. What QTE and range should be plotted in order to obtain a fix from the island? Var - 20W.
Ans - 135 degrees and 13nm.
The center of a small island is identified at the intersection of 60 degree left bearing line and 15nm range arc of airborne weather radar. If aircraft's heading and height are 035 degrees (M) and 42500 feet. What QTE and range should be plotted in order to obtain a fix from the island? Var - 20W.
Ans - 135 degrees and 13nm.
Join Date: Jan 2010
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Please help solve this question...
The center of a small island is identified at the intersection of 60 degree left bearing line and 15nm range arc of airborne weather radar. If aircraft's heading and height are 035 degrees (M) and 42500 feet. What QTE and range should be plotted in order to obtain a fix from the island? Var - 20W.
Ans - 135 degrees and 13nm.
The center of a small island is identified at the intersection of 60 degree left bearing line and 15nm range arc of airborne weather radar. If aircraft's heading and height are 035 degrees (M) and 42500 feet. What QTE and range should be plotted in order to obtain a fix from the island? Var - 20W.
Ans - 135 degrees and 13nm.
Var = 20w therefore True bearing is 315
QTE = 315-180=135
42500feet = 7nm
Use Pythag Distance = sqrt(15x15 - 7 x 7) =13.26 nm