Indigo Call letters for Freshers
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guyz can u plz help me these ques
An aircraft is flying at FL 140 where the COAT is -5° C. It is flying at an indicated air speed of 260 kts and is experiencing a headwind of 34 knots. When 150 nm from the FIR boundary it is instructed to reduce speed in order to delay arrival at the boundary by 5 minutes. The required reduction in indicated air speed is:
A) 33 kts.
B) 41 kts.
C) 24 kts.
D) 15 kts.
ans a
The time interval between the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the aircraft is 2 milli seconds. The slant range is:
A) 162 nm
B) 73 nm
C) 323 nm
D) 92 nm
ans is 162nm
A) 33 kts.
B) 41 kts.
C) 24 kts.
D) 15 kts.
ans a
The time interval between the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the aircraft is 2 milli seconds. The slant range is:
A) 162 nm
B) 73 nm
C) 323 nm
D) 92 nm
ans is 162nm
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IAS or CAS = 260 kts Find TAS which = 323 kts wind = 34 Headwind therefore Ground speed = 289 kts , Now time taken to cover 150Nm @ 289 = 31min.wit a delay of 5 min revised time = 36 min . Now speed = Distance/ Time therefore Speed @ delay of 5min= 150/36 min = 250 kts (ground speed) now convert 250 kts to TAS by adding 34 kts headwind which give you TAS of 284 kts using your flight computer Find CAS @ that TAS which equates to 228 kts ,,,,
now find the difference : 260 Kts -228Kts = 32 kts / 33kts
now find the difference : 260 Kts -228Kts = 32 kts / 33kts
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An aircraft is flying at FL 140 where the COAT is -5° C. It is flying at an indicated air speed of 260 kts and is experiencing a headwind of 34 knots. When 150 nm from the FIR boundary it is instructed to reduce speed in order to delay arrival at the boundary by 5 minutes. The required reduction in indicated air speed is:
A) 33 kts.
B) 41 kts.
C) 24 kts.
D) 15 kts.
ans a
The time interval between the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the aircraft is 2 milli seconds. The slant range is:
A) 162 nm
B) 73 nm
C) 323 nm
D) 92 nm
ans is 162nm
the first one seems dodgy but colsest i came was using cx2 using actual tas and a CAS of 226 ...i got an ans of 36 kts difference
2nd one is simple
distance = speed/time = 3*10^8 / 0.002 = 324
but this equals distance wave travels to stn and back so we divide by 2 we get 162
A) 33 kts.
B) 41 kts.
C) 24 kts.
D) 15 kts.
ans a
The time interval between the transmission of a given DME interrogation pulse and the reception of the appropriate response pulse at the aircraft is 2 milli seconds. The slant range is:
A) 162 nm
B) 73 nm
C) 323 nm
D) 92 nm
ans is 162nm
the first one seems dodgy but colsest i came was using cx2 using actual tas and a CAS of 226 ...i got an ans of 36 kts difference
2nd one is simple
distance = speed/time = 3*10^8 / 0.002 = 324
but this equals distance wave travels to stn and back so we divide by 2 we get 162
Maverick2167
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CONTACT NUMBER FOR CAE PEOPLE
Hii friends i have been trying to get a hall number for indigo assessment for pretty long time now ..can sum1 plz PM the contacts number for the cae people
any info will be appreciated
any info will be appreciated
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help needed
Whats the formula to calculate NDB range??
The nominal maximum range of an NDB with a transmitter power is 200 watts is:
A) 150 to 170 nm.
B) 200 to 220 nm.
C) 100 to 120 nm.
D) 50 to 60 nm.
Whats the formula to calculate NDB range??
The nominal maximum range of an NDB with a transmitter power is 200 watts is:
A) 150 to 170 nm.
B) 200 to 220 nm.
C) 100 to 120 nm.
D) 50 to 60 nm.
Join Date: Jan 2010
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the formula for NDB range is
over water (nm) = 3√Wattage
Over Land (nm) = 2√Wattage
So according to me the range of a 200 W NDB is 2√200 =28.3nm
is the answer in Km or nm??
over water (nm) = 3√Wattage
Over Land (nm) = 2√Wattage
So according to me the range of a 200 W NDB is 2√200 =28.3nm
is the answer in Km or nm??
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help please..
An aircraft is over flying a VOR at 30.000 ft, at a groundspeed of 300 kt. The maximum time during which no usable signals will be received (in minutes and seconds) is:
A)0.50
B)4.40
C)2.25
D)1:40
An aircraft is over flying a VOR at 30.000 ft, at a groundspeed of 300 kt. The maximum time during which no usable signals will be received (in minutes and seconds) is:
A)0.50
B)4.40
C)2.25
D)1:40
Join Date: Mar 2011
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guys can u plz help
A cambered airfoil with zero angle of attack, will in flight produce:
A) some lift and some drag.
B) no lift and no drag
C) some lift with no drag.
D) no lift but some drag.
A) some lift and some drag.
B) no lift and no drag
C) some lift with no drag.
D) no lift but some drag.
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