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ATPL theory questions

Old 22nd May 2017 | 20:25
  #1101 (permalink)  
 
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From: England
My comments were not intended to be taken seriously

But

If we take the river-crossing scenario, if the food is some distance downstream and the current is sufficiently slow, the dog might actually be moving at right angles to the flow, or even in a somewhat downstream direction when it reaches the food.

Or in the case of the Hare running directly away from the dog, the entire path of the dog will be a straight line. Given the range of possible scenarios, we cannot say that the path will always be a spiral or even a curve.

I have not bothered to go through the maths in the link, but if it is correct, then presumably it will cater for the cases examples which I have described above.
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Old 22nd May 2017 | 20:26
  #1102 (permalink)  
 
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From: France
Originally Posted by selfin
Paco,

Thanks for the heads up on the path being a pursuit curve. The derivation from first principles in terms of groundspeed coordinates was not going well!

The solution in airspeed coordinates appears to be given on the Wikipedia page for a radiodrome here, pushing the date back to at least the 1730s.
Ahah, it's look like i've found someone more mathematical than me !
You're seriously interested in coming up with an equation to describe this kind of curve ?
I'm sure you would be familiar with the brachistochrone curve as well ?
You sound like some of my colleagues in higher education who went on to become math researchers.
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Old 24th May 2017 | 20:59
  #1103 (permalink)  
 
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From: London, GB
For a pursuit starting with a non-zero crosswind component there will be at most only one instant when the headwind component is zero. The crosswind component will only be zero if the beacon is reached.

Nahin, referenced in the Wiki page on radiodromes, for a terrestrial coordinate system with the beacon at the origin and the wind acting along the positive y-axis, provides this function [eqn 1.2.8] for the radiodrome which he refers to as the "wind blown plane's path":



The wind speed is w and the true airspeed is v. At x = a, where the path crosses the x-axis, the heading is orthogonal to the wind. If n < 1, i.e. if the beacon can be reached, then the y-axis is an asymptote for y'(x). Therefore the beacon is reached directly from the downwind position unless it is initially approached directly from the upwind position.

KayPam,

That is a famous variational problem of similar vintage and one that took Newton half a day to solve.
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Old 25th May 2017 | 06:59
  #1104 (permalink)  
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He obviously had trouble with the ADF as well
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Old 25th May 2017 | 09:57
  #1105 (permalink)  
 
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From: England
Therefore the beacon is reached directly from the downwind position unless it is initially approached directly from the upwind position.
If I am understanding this comment correctly it means that:

Experiment 1. If the starting point is with the aircraft 10 km directly upwind of the beacon it’s final approach to the beacon will be from directly upwind.

Experiment 2. If we repeat the experiment, but with the aircraft displaced even a small distance (1 m, 1 cm or even 1 mm) to the left or right, it’s final approach to the beacon will be from directly downwind.

Is this really the case?

The limits of the resolution of the ADF system should not be a factor in this, because the same equations have been applied to other situations such as the dog and hare.

Last edited by keith williams; 25th May 2017 at 11:52.
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Old 25th May 2017 | 12:57
  #1106 (permalink)  
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From: France
Yes, I think that would be the case.
It's all about drift angle and not allowing for it.
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Old 27th May 2017 | 13:00
  #1107 (permalink)  
 
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From: London, GB
Strictly in terms of the properties of the curve that is correct. The required rate of turn near the beacon will however often exceed what can be achieved. Arthur Bernhart discusses these curves in a set of papers here.
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Old 10th June 2017 | 18:02
  #1108 (permalink)  
 
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From: Ghent
Originally Posted by Transsonic2000
Hi there,
I'd need some feedback regarding the following question - I believe that the answer provided is incorrect.

QDB says that the correct answer is 277.5 m but I come up with 279.7 m applying the following formula:

Domain 1/2 width = 60m + 1/2 wing span + 0.125 D
Domain 1/2 width = 60 + 32.2m + (0.125 x 1500m)
Domain 1/2 width = 279.7m

Thanks
For aircrafts with wingspan over 60m the formula is: 90m + 0.125D; so 90 + 0.125*1500 = 277.5m
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Old 12th June 2017 | 17:55
  #1109 (permalink)  
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The CAA response to post 1062:

Compressibility is typically considered at speeds above 200 kt CAS or 300 kt TAS.

However, it doesn't appear to be in the database anyway.
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Old 12th June 2017 | 22:25
  #1110 (permalink)  
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From: Bristol, England
Bless them, this is because the FAA documentation says compressibility need not be considered below 200KT (one assumes CAS but they don't specify) and 10,000ft (missed that bit out) and the CRP-5 and its RAF predecessors did not consider compressibility below 300KT TAS. The response is an awkward attempt to reconcile the two given speeds, but sadly misses the point that compressibility is not applied in the conversion between Mach number and TAS. Really.
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Old 25th June 2017 | 21:03
  #1111 (permalink)  
 
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From: France
Hey,

Having just completed my 14th test a few days ago, I'd like to provide you with some feedback.
I started with a French School in mid december, so it took me a grand total of 6 months and one week. That's including the four total weeks I took to revise before sessions 1, 2 and 4.

My country does not seem to be willing to disclose your marks, but I had an average of about 95-96% with my school's final tests (they reused some questions from aviationexam and created some questions, to simulate new questions on the test day)

I spent half my time on the books and half my time on aviation exam.
This was done in parallel with my job, about 1 to 3 hours per day of work, every day during these six months.

About the subjects :
I started with :
Communications, air law, ops proc : just by heart learning, not so many new questions but they could be surprising since it's not easy to not miss anything.
Then, instruments, meteorology, perf and mass&balance : No idea if questions on test day were new or not because they could all be answered with reasoning. I like subjects like these.
Then AGK, PoF, flight planning. The latter two are like the four previous one : I liked them. However I feel AGK is the subject in which the level I reached is the weakest of all subjects : too many many systems and details to learn. Different type of fire detectors, seriously ?
To finish with, gen nav, radionav, human factors.
HF : easiest subject of all, took me 10 minutes to complete the test.
Gen nav : so many calculations, it makes me tired. Thankfully it's quite of an easy subject for an ex math-student like me.
Radionav : worst subject, by far. Many different themes and many new questions about ridiculous little details that no one cares about.. The subject in which I had the worst scores, immediately after having read the books. In the end I think I have a better command of this subject than AGK but it was a pain in the ass. Probably mostly because it was the last subject.

Now i'm on for some bureaucracy to get my official diploma.

I'm very glad it's over, I have no idea what I'm going to do with all the newly available free time.
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Old 28th June 2017 | 21:05
  #1112 (permalink)  
 
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From: Abuja
Hello, I came across a difficult PSR/PNR question while writing SACAA IR Exams and I need your help. Twice infact and all were similar.

I was given a PET Distance of I think 1200nm and distance from point A- B of 2300 NM if I remember correctly. Total fuel was about 15000kg and that was all. No speeds or endurance was given or wind. I was then asked to calculate PSR from point A to B.
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Old 11th July 2017 | 23:03
  #1113 (permalink)  
 
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From: Earth
Hi there

I started studying from the syllabus learning objectives, means that I learn specifically what they are willing us to know, line by line.
Do you think that's a good technique to pass the ATPL theory exams?! Or I should only study from my notes/books/cbt,... ?!
I am quite worry as the official exams are fastly coming up...

Cheers
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Old 12th July 2017 | 06:13
  #1114 (permalink)  
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In that case you will learn to navigate before you know about Lat & Long......

Not a good idea that. The LOs were never meant to be a syllabus as such.
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Old 12th July 2017 | 19:13
  #1115 (permalink)  
 
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From: East Sussex
Hey Pacol, then why put LO's in? What's the point of covering LO's if they don't (at the very least) cover the syllabus? Can you point me to the syllabus per se? That way I won't have to worry about the LO's
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Old 13th July 2017 | 05:50
  #1116 (permalink)  
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There are no syllabuses, that's the rub! They specify an LO, meaning what a student is expected to know after the studying then leave it up to the schools to guess to what level they should teach, thus creating their own syllabus. The only reference to levels or even sources of knowledge is in the question itself, which nobody should be able to see.
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Old 13th July 2017 | 06:49
  #1117 (permalink)  
 
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From: eu
Originally Posted by fly5N
Hello, I came across a difficult PSR/PNR question while writing SACAA IR Exams and I need your help. Twice infact and all were similar.

I was given a PET Distance of I think 1200nm and distance from point A- B of 2300 NM if I remember correctly. Total fuel was about 15000kg and that was all. No speeds or endurance was given or wind. I was then asked to calculate PSR from point A to B.
Hello maybe I can contribute to the question because I had a similar one,

I got during my IR rating exam an interesting PSR\PNR question where I am going right now crazy to get to a solution. I asked now already everyone at flight schools, looked in different forums, but could not find an answer. I even asked already the authority, but they were not authorized to help me...

Hopefully you guys can help me here with a solution.

The question simple:
- distance A to B 2000NM
- TAS, wind, endurance constant
- 5000kg fuel (+500kg extra)
- PET from A 1200NM

what is the PNR\PSR?

answeres: I cant remember the values any more but for the approach process it should be not an issue. There were 5 answeres and I chose c.) which was 1200NM (same as PET and which is wrong).

My approach was the following, due to the fact that there are to less variables for calculations, no given fuel flow,..., it's more a theoretical question. TAS, wind, endurance are constant, so I thought it might be one of the rare cases where PET=PSR, which leads me to another question:
- Can PSR be equal PET and\or is PSR always more\less then PET?

I assume that when there is no wind and PET is exactly half of the distance, is there also PSR half of the distance or more\less?

In the example above I know I have headwind doe to the fact that PET is closer to B, so if PSR is maybe always more then PET then there might was only one answer which was more then 1200nm...

Or maybe I am completely wrong...,
anyways, appreciate your help in this case!
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Old 13th July 2017 | 06:58
  #1118 (permalink)  
 
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From: eu
And maybe another question which is right now a little bit a pain in my ass, where even after discussion with mechanics I came to no solution.

Which TWO instruments are adversely affected by an electrical power failure in flight?:
A. ASI
B. Magn. compass
C. DI
D. AI
E. CDI

A and b definitely not. I would have chosen c,d,e but the question said TWO, and now i am strungling. The discussion with the mechanics ended up that it's c and d, but also a cdi could be affected depending on an old or new one...

So hopefully someone here knows the right answer and can explain why.

Appreciate it, thx
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Old 13th July 2017 | 12:19
  #1119 (permalink)  
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The compass is swung with all the electrics on, so if they fail, the deviation card will be inaccurate.
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Old 14th July 2017 | 07:36
  #1120 (permalink)  
 
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From: eu
Thx for this true statement, unfortunately helps not for the answer to the question.
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