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Specific Gravity Question?


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Specific Gravity Question?

Old 27th June 2006 | 17:48
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Specific Gravity Question?

Hello

I would like a clarification please.

1 USG = 6lbs - does this already take into account a SG of 0.72?

So for my calculations 34 USG = 204 lbs (34*6)

also is it correct to say 1 USG = 3.785 litres and therefore 34 USG = 128.69 litres?

(phew) Thank you in advance...
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Old 27th June 2006 | 21:05
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1 USG = 3.78L
3.78L x 0.72SG = 2.7216kg
2.7216kg = 6lbs

or 1USG = 6lbs!

So yes it does take into account the specific gravity
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Old 28th June 2006 | 08:33
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[Pedantic mode] Technically, it is incorrect to multipy volume by SG to determine weight. In reality however, the difference is so small for a/c-sized fuel volumes that it makes no practical difference. (quite a difference for VLCC's though )

Assuming 1 USG = 6lb, then the density@15C of the fuel is 0.7201 and the SG@60F is 0.7203

[/Pedantic mode]
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