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Specific Gravity Question?
Hello
I would like a clarification please. 1 USG = 6lbs - does this already take into account a SG of 0.72? So for my calculations 34 USG = 204 lbs (34*6) also is it correct to say 1 USG = 3.785 litres and therefore 34 USG = 128.69 litres? (phew) Thank you in advance... |
1 USG = 3.78L
3.78L x 0.72SG = 2.7216kg 2.7216kg = 6lbs or 1USG = 6lbs! So yes it does take into account the specific gravity |
[Pedantic mode] Technically, it is incorrect to multipy volume by SG to determine weight. In reality however, the difference is so small for a/c-sized fuel volumes that it makes no practical difference. (quite a difference for VLCC's though :8 )
Assuming 1 USG = 6lb, then the density@15C of the fuel is 0.7201 and the SG@60F is 0.7203 [/Pedantic mode] |
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