ok.... here's the next batch of questions..... once again, the degrees symbol has been turned into a '1'.... hope these are helping....
PPSC REVISION QUESTIONS
SECTION 4 - 061 04 - DR NAVIGATION
1 Given: GS = 510kts; distance A to B = 43nm
What is the time (min) from A to B?
a. 7
b. 5
c. 4
d. 6 1 min (1)
2 Given: True track 3521
Variation 111W
Deviation is -51
Drift 101R
Calculate the compass heading.
a. 3581
b. 3461
c. 0181
d. 0251 1 min (1)
3 Given: True course from A to B = 0901
TAS = 460 kts
W/V = 360/100
Average variation = 101E
Deviation = -21
Calculate the compass heading and GS.
a. 0691 - 448kts
b. 0681 - 460kts
c. 0781 - 450kts
d. 0701 - 453kts 3 min (3)
4 Given: IAS 120kts
FL80
OAT +201C
What is the TAS?
a. 102kts
b. 120kts
c. 132kts
d. 141kts 1 min (1)
5 An aircraft travels 100 statute miles in 20 min. How long does it take to travel 215nm?
a. 50 min
b. 80 min
c. 90 min
d. 100 min 1 min (1)
6 What is the ratio between the litre and the US-GAL?
a. 1 US-GAL equals 4.55 litres
b. 1 litre equals 3.78 US-GAL
c. 1 US-GAL equals 3.78 litres
d. 1 litre equals 4.55 US-GAL 1 min (1)
7 An aeroplane is flying at TAS 180kts on a track of 0901. The W/V is 045/50kts. The distance that the aeroplane can fly out from its base and return in one hour is:
a. 56nm
b. 85nm
c. 88nm
d. 176nm 2 min (2)
8 For a landing on runway 23 (2271 Magnetic) surface W/V reported by the ATIS is 180/30kts; variation is 131E. Calculate the cross wind component?
a. 15kts
b. 20kts
c. 23kts
d. 26kts 2 min (2)
9 Given: TAS = 472kts
True HDG = 0051
W/V = 1101/50kts
Calculate the drift angle and GS.
a. 61R - 487kts
b. 71R - 491kts
c. 71L - 491kts
d. 61L - 487kts 2 min (2)
10 Given: TAS = 227kts
Track (T) = 3161
W/V = 2051/15kts
Calculate the HDG (1T) and GS.
a. 3111 - 230kts
b. 3121 - 232kts
c. 3131 - 235kts
d. 3101 - 233kts 2 min (2)
11 Given: Magnetic track = 2101
HDG = 2151(M)
VAR = 151E
TAS = 360kts
The aircraft flies 64nm in 12 min
Calculate the W/V (1T)
a. 195/52kt
b. 355/15kt
c. 263/50kt
d. 258/53kt 2 min (2)
12 Given: True HDG = 1451
TAS = 240kts
Track (1T) = 1501
GS = 210kts
Calculate the W/V
a. 115/35kt
b. 180/35kt
c. 295/35kt
d. 360/35kt 2 min (2)
13 Given: TAS = 155kts
HDG (1T) = 2161
W/V = 0901/60kts
Calculate the Track (1T) and GS
a. 2221 - 181kts
b. 2241 - 175kts
c. 2261 - 186kts
d. 2311 - 196kts 2 min (2)
14 Indicated outside air temperature -301C; TAS 438kts. What is the COAT?
a. -351C
b. -411C
c. -471C
d. -501C 1 min (1)
15 Given: Pressure Altitude = 29000ft
OAT = -501
Calculate the Density Altitude.
a. 26000ft
b. 27000ft
c. 31000ft
d. 33500ft 2 min (2)
16 The distance Q to R is 3016nm; TAS is 480kts. Flying outbound Q to R the headwind component is calculated as 90kts and the tailwind component R to Q is 75kts. Leaving Q at 1320UTC, what is the ETA at the Point of Equal Time?
a. 1631UTC
b. 1802UTC
c. 1702UTC
d. 1752UTC 2 min (2)
17 An aircraft was over Q at 1320UTC flying direct to R.
Given: Distance Q to R 3016nm
True Airspeed 480kts
Mean wind component 'out' -90kts
Mean wind component 'back' +75kts
Safe endurance 10:00 hours
The distance from Q to the Point of Safe Return (PSR) is:
a. 2370nm
b. 2290nm
c. 1310nm
d. 1510nm 2 min (2)
18 Given: M0.9
FL370
OAT -701C
Determine CAS:
a. 500kts
b. 281kts
c. 293kts
d. 268kts 2 min (2)
19 Given: Pressure Altitude = 27,000ft
Mach No = 0.45
OAT = -351C
W/V = 270/85
Track = 2001(T)
What is drift and groundspeed?
a. 181L 252kts
b. 151R 310kts
c. 171L 228kts
d. 171R 287kts 2 min (2)
20 Given: GS = 240kts
Distance to go = 500nm
What is time to go?
a. 20 mins
b. 29 mins
c. 2 hrs 05 mins
d. 2 hrs 12 mins 1 min (1)
21 Given: Pressure Altitude = 5,000ft
OAT = +351C
What is true altitude?
a. 4550ft
b. 5550ft
c. 4290ft
d. 5320ft 1 min (1)
22 Given: Course = 0401(T)
TAS = 120kts
Wind speed = 30kts
From which direction will the wind give the greatest drift?
a. 2151(T)
b. 2401(T)
c. 2351(T)
d. 2301(T) 2 min (2)
23 Given: Required Course = 0451(T)
W/V = 190/30
FL = 55
OAT = ISA
Variation = 151E
CAS = 120kts
What is Magnetic Heading and GS?
a. 0521(M) 154kts
b. 0671(M) 154kts
c. 0371(M) 154kts
d. 0371(M) 113kts 2 min (2)
24 The Compass Heading is 0901(C). Deviation is 21W and Variation is 121E. The TAS is 160kts. The aircraft is on the 0701 radial outbound from a VOR and has flown 14nm in 6 minutes. What is the W/V?
a. 048/51
b. 160/50
c. 340/25
d. 055/25 2 min (2)
25 Given: Course = 0401(T)
TAS = 120kts
Wind speed = 30kts
From which direction will the wind give the greatest drift?
a. 1401(T)
b. 1351(T)
c. 0901(T)
d. 1001(T) 2 min (2)
26 Given: Groundspeed = 540kts
Distance to go = 72nm
The time to go is:
a. 8 mins
b. 9 mins
c. 12 mins
d. 18 mins 1 min (1)
27 An aircraft is on a 31 ILS glideslope which passes over the runway threshold at 50ft. The DME range is 25nm from the threshold. The height above the runway threshold elevation is:
a. 8010ft
b. 7450ft
c. 6450ft
d. 7650ft 2 min (2)
28 Given: Pressure Altitude = 29,000ft
SAT = -551C
The density altitude is:
a. 27,500ft
b. 26,000ft
c. 30,000ft
d. 31,000ft 1 min (1)
29 Given: Distance A to B = 2368nm
Groundspeed outbound = 365kts
Groundspeed homebound = 480kts
Safe endurance = 8hrs 30min
The time to the PNR is:
a. 290 minutes
b. 209 minutes
c. 219 minutes
d. 190 minutes 2 min (2)
30 An aircraft is on a 12% glidepath; the groundspeed is 540kts. The rate of descent required is:
a. 6550'/min
b. 4820'/min
c. 8740'/min
d. 3120'/min 2 min (2)
PPSC JAR REVISION QUESTIONS
SECTION 4 - 061 04 - DR NAVIGATION
Answers:
1 b
2 a
3 a
4 d
5 a
6 c
7 b
8 c
9 d
10 b
11 c
12 a
13 d
14 d
15 b
16 d
17 b
18 c
19 c
20 c
21 b
22 b
23 c
24 b
25 b
26 a
27 d
28 a
29 a
30 a
good luck everyone