Question1
Range (nm) = 1.25 sq root ht. of transmitter + 1.25 sq. root ht of reciever
300 =1.25 sq root 2500 + 1.25 sq root ht of rec.
300 = 62.5 + 1.25 sq root ht of rec
300-62.5 = 1.25 sq root ht of rec
237.5 =1.25 sq root ht of rec
237.5/1.25= sq. root ht of rec ( Assume this to be X feet amsl )
190 = sq root x
sq. both sides
x= 36100 feet
Hence, the close option is C
Question2
Same formula to be used for this question, just that this tym range is to be calculated.
Range (nm) = 1.25 sq root 19000 + 1.25 sq. root 1400
= 172.30 +46.77
=219 nm approx
Hence, close option is D
Correct me if I'm wrong.!