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Different landing distance with/without rev thrust

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Different landing distance with/without rev thrust

Old 5th Oct 2018, 13:24
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Different landing distance with/without rev thrust

Hi,

This is a performance question. I've looked up FCOM 1 for the different landing distance based on landing with/without reverse thrust.

My thought is the rate of deceleration after landing is the same with or without reverse thrust with the use of Autobrakes.

If so, why does FCOM directs me to add an adjustment to the landing distance with autobrake 1, No Reverser on a dry runway and also on a Good Braking Action runway with varying autobrakes settings with No Reverser? The rate of deceleration should be the same and if so, shouldn't the landing distance be the same too?

Thanks for the enlightenment.
extricate is offline  
Old 5th Oct 2018, 14:58
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I would think: Friction of the tires on the runway is proportional to normal force (the weight of the plane pressing down on them). At the beginning of the landing run, there is still substantial lift from at least part of the wing, even with spoilers deployed, reducing the effective weight on the wheels, and thus the friction available for braking.

Therefore, a rate-based autobrake system just won't have enough braking to work with, until the plane slows enough and puts enough weight on the wheels. Reverse gets you down to a speed where the brakes become fully effective, in less time and thus in less distance.

At which point the autobraking will give a constant rate of deceleration (if so designed), based on the combination of reverse thrust (if used) and friction braking.
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Old 5th Oct 2018, 16:33
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Autobrakes can give you less braking than is available by the conditions of the day, it can't give you more. If you are in a state where the max available braking action is less than that which the autbrakes is trying to achieve, then you will be limited by the conditions. In which circumstances changing the conditions - by, for example, using TRs - should change your stopping performance.
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Old 5th Oct 2018, 17:44
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Depending on the autobrake setting on your type, you should have reversers slowing you before the autobrake kicks in ( eg 4 seconds on the A320 with autobrake low)
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Old 6th Oct 2018, 01:42
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Originally Posted by pattern_is_full View Post
I would think: Friction of the tires on the runway is proportional to normal force (the weight of the plane pressing down on them). At the beginning of the landing run, there is still substantial lift from at least part of the wing, even with spoilers deployed, reducing the effective weight on the wheels, and thus the friction available for braking.

Therefore, a rate-based autobrake system just won't have enough braking to work with, until the plane slows enough and puts enough weight on the wheels. Reverse gets you down to a speed where the brakes become fully effective, in less time and thus in less distance.

At which point the autobraking will give a constant rate of deceleration (if so designed), based on the combination of reverse thrust (if used) and friction braking.
This makes sense.

Thanks for all the replies above.

Please share more
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Old 13th Oct 2018, 09:07
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Whilst on ground school for the 146 some 20+ yrs ago we were told that regulatory requirements did not take into account reverse thrust for landing distance requirements, it was an unaccounted stopping bonus. Thus on the 146 the landing distance required was increased by 10% as it didn't have RT.

https://flightsafety.org/files/alar_bn8-3-distances.pdf

When discussing landing distance, two categories must be considered:
  • Actual landing distance is the distance used in landing and braking to a complete stop (on a dry runway) after crossing the runway threshold at 50 feet; and,
  • Required landing distance is the distance derived by applying a factor to the actual landing distance.

    Actual landing distances are determined during certification flight tests without the use of thrust reversers.
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