Go Back  PPRuNe Forums > Flight Deck Forums > Tech Log
Reload this Page >

Calculate Lift Coefficient

Wikiposts
Search
Tech Log The very best in practical technical discussion on the web

Calculate Lift Coefficient

Thread Tools
 
Search this Thread
 
Old 3rd May 2015, 23:49
  #1 (permalink)  
Thread Starter
 
Join Date: Sep 2011
Location: Milan
Age: 34
Posts: 5
Likes: 0
Received 0 Likes on 0 Posts
Calculate Lift Coefficient

I'm trying to figure out what's the lift coefficient of an A320. What I'm doing is the following: during cruise, the lift is equal to the weight of the aircraft (mg) so that I used the cruise table taken from the FCOM to get the speed, the wing area is known (122.6 m^2) and I calculated using an online tool the air density at FL290 (29000ft):

http://i.stack.imgur.com/l9g9N.png

The result is that the lift coefficient is 0.03029. Is it right for the assumptions given above? Next, if I want to relate the Cl with the Angle of Attack, what is the formula and the procedure? Thank you for your help.
Cpt. A380 is offline  
Old 4th May 2015, 01:42
  #2 (permalink)  
 
Join Date: Feb 2001
Location: Milkway Galaxy
Posts: 240
Likes: 0
Received 0 Likes on 0 Posts
Capt. A 380
I do not think it is so easy practically calculate CL with simple arithmetic. This is because every component of airplane (e.g fuselage) has effect on resultant aerodynamic force.

But just one contribution: L=W is incorrect,
The correct one is : L=W+Td,

What is Td?
I can describe it as the downward lift force created by Horizontal Stabilizer to equalize the moments about CG to zero. In another word, it is the downward force to create a counter moment to balance the moment created by wing.
JABBARA is offline  
Old 4th May 2015, 08:51
  #3 (permalink)  
 
Join Date: Jun 2001
Location: Boldly going where no split infinitive has gone before..
Posts: 4,785
Received 44 Likes on 20 Posts
Jabbara,

I don't agree with that. Lift is the sum of all vertical forces on the aircraft, and in cruise is equal to weight. Yes, the wing has to produce extra lift to over come the downforce of the tail (in most aircraft- some models actually have a lifting tail), but total lift is the sum of these.

Co-efficient of lift refers to the whole airframe, not just the wing, so entering values to the equations L=C 1/2 RHO V^2, with the assumption that in cruise L=W is valid as far as I can see.
Wizofoz is offline  
Old 4th May 2015, 09:48
  #4 (permalink)  
 
Join Date: Oct 2011
Location: United Kingdom
Posts: 310
Likes: 0
Received 0 Likes on 0 Posts
You're method seems sound but the answer you have is too low. Conversion of TAS from kts to m/s perhaps? I ran through it and got Cl = 0.3 ish.

As a first approximation, CL = Cl_alfa * AoA, where Cl_alfa is a constant dependent on aerofoil and wing geometry. Good luck finding any accurate numbers for the A320, but I think Cl_alfa = 5-6 rad^-1 is the rough range.

As others have pointed out, this method gives the effective "whole aircraft" Cl. To get the Cl for the wing in isolation and a true AoA much more detail regarding the tailplane, fuselage lift contribution etc etc would be needed. As a rough approximation though it shouldn't be too far out.
ManUtd1999 is offline  
Old 4th May 2015, 10:08
  #5 (permalink)  
 
Join Date: Jun 2011
Location: West of Offa's dyke
Age: 88
Posts: 476
Likes: 0
Received 0 Likes on 0 Posts
Check your units.
As Man.Utd said, for the conditions you cite the overall CL is 0.27
m - kg
g - m/sec squared
rho - kg/ m cubed
TAS - m/ sec
Area - m squared

Depending on CG the tail lift will be in the range 2 to say 8% of the total so the wing lift will be that much higher. To get an exact value you need detailed aerodynamic information that is almost never published.

The aoa will depend on flap setting and Mach number, but again needs unpublished detail. As a ballpark figure use aoa = 10 times CL (aoa in degrees)
Owain Glyndwr is offline  
Old 4th May 2015, 14:47
  #6 (permalink)  
 
Join Date: Feb 2001
Location: Milkway Galaxy
Posts: 240
Likes: 0
Received 0 Likes on 0 Posts
To get an exact value you need detailed aerodynamic information that is almost never published
I totally agree


Hi Wizofoz
Lift is the sum of all vertical forces on the aircraft, and in cruise is equal to weight. Yes, the wing has to produce extra lift to over come the downforce of the tail
I agree, I mean the same.

some models actually have a lifting tail
This is mostly correct for naturally designed unstable fighter jets (but to be controlled only by FBW), not for Transport Category Airplane

Co-efficient of lift refers to the whole airframe, not just the wing
, I agree, I mean the same

Of course I agree with the equation "
so entering values to the equations L=C 1/2 RHO V^2,
but "S" is missing.

But my knowledge of Flight Mechanics tells me here: L is always bigger than W. As below.




[/IMG]





At the end, I am not an expert, I may be missing something. if correct me I will be happy.

Thanks

Last edited by JABBARA; 4th May 2015 at 14:53. Reason: Addition quotation from O.Glyndwr
JABBARA is offline  
Old 4th May 2015, 16:03
  #7 (permalink)  
 
Join Date: Aug 2012
Location: Wales
Posts: 532
Likes: 0
Received 0 Likes on 0 Posts
If you are counting in the tailplane component, then you could also include the upward thrust from the engines. This depends upon their alignment, and will increase at slower speeds as AoA increases (towards say +14 deg.).
phiggsbroadband is offline  
Old 4th May 2015, 20:35
  #8 (permalink)  
 
Join Date: Jun 2011
Location: West of Offa's dyke
Age: 88
Posts: 476
Likes: 0
Received 0 Likes on 0 Posts
Thrust contribution

Yes in principle, but in cruise T/W around 5 or 6%, aoa around 1/15 radian, vertical component of thrust only about 0.4%W - negligible compared to other contributions
Owain Glyndwr is offline  

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off



Contact Us - Archive - Advertising - Cookie Policy - Privacy Statement - Terms of Service

Copyright © 2024 MH Sub I, LLC dba Internet Brands. All rights reserved. Use of this site indicates your consent to the Terms of Use.