:Bingo!!!!!Cheers LOFT:D
It will be highly appreciated if u can solve it here in details

Q2.De Compression Sickness is related with
1. Henry's Law
2. Dalton Law
3. Boyle Law
4.Charles law

Henrys Law of Gases - Nitrogen forming bubbles and escaping out of tissues.
:ok:

Hey guys,hv a small doubt..wot is the accuracy of DME acc to ICAO standards,is it 0.25nm+1.25% of range or (.5 or 3% of range)??

I believe its 0.5Nm or 3% which ever is higher

@LOFT-U r right again.Guys every body post some question also...
Q3.What are frangible objects?

DME Accuracy is + - 0.2nm as per the latest ICAO Annex ;
( and 0.25 nm + 1.25 % of range for older aircraft, older than 1989)

Frangible = brakeable (easily broken)

:ok:

@aviator4u-

it is .25nm 1.25%if u go by oxford and .5nm 3% if u go by GSP. I'll rather prefer oxford over GSP at this stage. :ok:

@pradeep747-

objects which tend break into fragments if deformation force applied.:ok:

CHEERS..!!

How does leading and trailing edge flaps affect critical angle of attack ?

Why is Vmcg determined with nosewheel steering disconnected ??:ugh:

Disengaging the Nosewheel Steering provides a wet runway simulation.
:ok:

@LOFT-

What about my previous ques.?

Leading edge flaps Increases critical AOA and trailing edge reduces critical AOA

Basically you can pitch up higher when using the Leading edge devices and lesser with the Trailing edge flaps in comparison to the Clean configuration.
:ok:

Nice work guys....btw..all these questions being posted from oxford??

The lift coefficient (CL) of an aeroplane in steady horizontal flight is 0.42. An increase in angle of attack of 1 degree increases CL by 0.1. A vertical up gust instantly changes the angle of attack by 3 degrees. The load factor will be:

1.71
1.49
2.49
0.74

Request u to put up an explained answer.

[IMG]file:///C:/Users/yogesh/AppData/Local/Temp/moz-screenshot-7.jpg[/IMG][IMG]file:///C:/Users/yogesh/AppData/Local/Temp/moz-screenshot-8.jpg[/IMG]

the answer is 1.71
heres the explanation well its another example hope it helps u
Example 1.
An aeroplane is flying straight and level with a coefficient of lift of 0.55. The coefficient of lift
increases by 0.08 per degree increase in angle of attack. If a vertical gust increases the angle of
attack by 3º, what is the load factor?
Since the vertical gust increased the angle of attack by 3º the coefficient of lift will have increased
by 0.24 (0.08 x 3), and the new coefficient of lift is 0.79 (0.55 + 0.24). Since the coefficient of lift
and lift are proportional to the load factor the new load factor is 0.79/0.55 = 1.44. The new load
factor is therefore 1.44 and if the question had asked for the increase in load factor this would be
0.44.
Example 2
What is the percentage increase in lift if the angle of attack increases by 4º due to a vertical gust.

Load factor is 1.71
 

@ wings on fire
Let's assume lift is propotional to CL since other factors are not changing

Load factor = lift(produced at that instant/ wing loading/ wt
Here let's call AOA as variable 'x' fr simplicity

CL= k*x. k is a constant for all other variables which are nit changing like wing area, density etc

0.42=k*x
0.52=k*(x+1)

When AOA changes by 3 deg equation becomes
CL=k*(x+3)

Substitue values frm above equation n get CL= 0.72 when gust is experienced.

Now go back to st n level condition

Load factor=1
that means wt= lift in this case which is 0.42

Load factor in gust= lift(in gust)/ wt(which is constant)

Load factor = 0.72/0.42
= 1.71

Cheers

@ wings on fire
Hi.... Have you got the payment mail yet,,? .... i got the first mail on 3 DEC too and haven't got any reply yet :sad:

Thanks for the help guys:)
@Maverick:I got the payment mail about an hour ago!!

anyone got the payment conformation or the hall ticket mail yet?

guys are all these questions from oxford??

@kinko-not all r from oxford

4. In what way is the longitudinal stability affected by the degree of positive camber of the aerofoil?

@pradeep
specify the airfoil you are talking about

in case of wings ... the longitudinal stability would decrease
in case of horizontal stabilizer/elevator ... long. stability would increase

answer is No effect because camber of the aerofoil produces constant pitch down moment independent of AOA

Help Needed
 

Q-An aeroplane performs a steady horizontal turn with a TAS of 200 kt. The turn radius is 2000 m. The load factor (n) is approximately:
a)1.1
b)1.4
c)1.8
d)2.0

It says answer is 1.1

@pradeep747-could you check your inbox

And 1.1
 

Firtst find out the angular velocity of the aircraft.
Angular velocity(omega)= V(TAS)/r(radius)

Take proper units . You will get omega in radians/sec.
Now convert that into degrees//sec and you will get 3deg/sec.

That means rate one turn. So find angle of bank by 10%TAS+7.

Now load factor= 1/cos(angle of bank)
L=1.1


Cheers

i doubt if such question would come... its an examnination for the freshers

@flying rocks 320
 

Absolutely!!!

Thank u very much Euindkan..its so simple and i was taking it big and faltered.

@flyrock& Dynamite- Expect these kind of question and these are the question which is going to make u clear the exam and remember they are not looking us as freshers but as future AIRLINE PILOTS(sorry if i am hard & pl come out the freshers shell) and that was a simple q which needs little thinking(Of course i dint do it),still i hunted for the answer and got it...

What are the basic elements transmitted by NAVSTAR/GPS satellites?
offset of the satellite clock from GMT
i ephemeris data
ii health data
iii ionospheric delays
iv solar activity

A) i, ii, iv
B) ii, iii, iv
C) i, ii, iii, iv, v
D) i, ii, iii

In relation to the satellite navigation system NAVSTAR/GPS, "All in View" is a term used when a receiver:

A)is tracking more than the required 4 satellites and can instantly replace any lost signal with another already being monitored

B) is receiving the signals of all visible satellites but tracking only those of the 4 with the best geometric coverage

C) requires the signals of all visible satellites for navigation purposes

D) is receiving and tracking the signals of all 24 operational satellites simultaneously


Are these kind of questions expected..?

You have altered the question. But not given correct options.....

Correct Answer : Offset of the satellite clock from GMT, Ephemeris Data and Ionospheric Delay.

Which of the following statements is correct concerning the principle behind the correction of one of the NAVSTAR/GPS satellite navigation system errors by the transmission of the signals on two frequencies (L1 and L2)?

A)The effect of receivers noise can be reduced due to the interference of both frequencies

B)The influence of shadowing on the GPS signals is proportional to the inverse of the carrier frequency squared

C)The path delay of the signals in the earth atmosphere is proportional to the inverse of the carrier frequency squared

D)The effect of signal reflections (multipath effect) can be reduced due to the interference of both frequencies

How Much Hrs. Or Amount Of Studying Required?
 

Dear Indigo Applicants,

Good luck once again on getting the letter and all d best for the d-day!
just wondering , considering the level of difficulty on different aspects involved in these Indigo selection tests, what amount of studying and how much vastness /level of knowledge would one grade fair to even attempt to guarantee success?

The comparison can be done on the basis of knowledge one might have from
1.DGCA/ ICAO exams?
2.CPL or ATPL level complexity?
3.Performance (a/c loading etc.) or just Plain -cpl -level navigation knowledge
reqd?
4.Compared to other airline exams , where would you rate Indigo's test at ?

Your response ( especially from previous takers of the tests / experienced pilots / applicant who've experienced diff tests at diff. levels ) would be highly appreciated.
(Only serious comments plz.)

Thanks for your time,
CR:ok:

32) Two identical turbojet aeroplanes (whose specific fuel
consumption is assumed to be constant) are in a
holding pattern at the same altitude. The mass of the
first one is 95 000 kg and its hourly fuel consumption is
equal to 3100 kg/h. Since the mass of the second one is
105 000 kg, its hourly fuel consumption is:
A) 3787 kg/h
B) 3426 kg/h
C) 3259 kg/h (Mark scheme answer)
D) 3602 kg/h
->My workings: 3100/95000=0.03263*105000=3426.3kg/h???

hey guys...
those u hav got the letter for payment...wts d last date for making payment ???
and has anyone got the letter regading the final date n centre yet???
all the best evryone...study hard...

@love2fly8510

The last date of payment is 10th Dec.
and I doubt if anyone has got hall tickets till now.