You are flying at an altitude of 35,000 ft , what is approximate range of your commun
 

You are flying at an altitude of 35,000ft what is approximate rang of your communication

200 nm
400 nm
1500 nm

Approximately 230.11192887 :)

Phil

I'm about to be guilty of being absolutely no help whatsoever (!), but really? You need to ask that on here? You roused my curiosity because I found myself having completely forgotten the theoretical formula, but a 20 second google search led me to the answer. Much quicker than waiting for replies on here as well, although paco's already given the answer for you.

Ok, ok, I won't be completely unhelpful, the formula is 1.23 multiplied by the square route of the altitude in feet.

:ok:

Thanks PAco and Ei-flyer

My curiosity is aroused as well. This type of question is not at all unusual on the wannabes forum, and is the sort of question you might well expect to see of a trainee pilot.

What I find a bit unusual is why somebody who professes to have 5000 hours on jets with 5 type ratings, would be asking something so basic?

This and the question that you have asked in the Questions forum concerning the application of mach number, would suggest there were some enormous gaps in your training whilst amassing those 5000 hours on jets?

In the freight dogs forum you recently (yesterday) claimed to have turned down a job with "Air Hong Kong on an A300-600F" because they offered you a 5 year contract with an $85,000 bond attached.

Possibly my perception is erroneous, but you seem to be a remarkably experienced "wannabe" with some remarkable gaps in your knowledge?

07th November 2010 18th November2010 22nd November 201012th December 201026th December 2010

Nevermind the equation, you cant do that in your head. 6x your altitude is a good rule of thumb and works close enough. 6x35=210 miles.

I like the six by alt rule. I was taught 12 x sq rt of FL, which is essentially the same as 1.2 x sqrt alt in feet.

Bealzebub, maybe whitecross is Tim Martins

He also claims to be 99 yrs old??

Whats more worrying - this guy making up a life he doesn't lead, or Bealzebub stalking the hell out of him haha jk

Happy new yr

I was taught 1.25 x square root alt (although there was some discussion at the time whether 1.23 was the newly preferred figure).

Of course, in reality I would appeal the question - What comms system (VHF/HF/SATCOM etc) am I meant to be using? :)

The UK CAA used to use 1.25, the rest of the world used 1.23. The current JAA syllabus uses 1.23. The difference between the two factors is less than 2% and the formula is only an approximation anyway, including an element for refraction and ducting in VHF/UHF.

More discussion here.

Why do you assume, misjudge and just speak for the sake of speaking
 

Bealzebub :ugh::ugh::ugh:Its not nice to assume or judge people just for the sake of writing or speaking .I dont need anybody or any help to answer this question , but i was on a research with a friend how much replies and accuracy we get on such a question. There is no harm in asking any question here and i am not hurting anyone. So Please try act like a Grown-up.:)

Then please accept my humble apologies and a promise that I will attempt to grow up.

It just wasn't clear that you already knew the answer and were simply testing people to see what they knew? That, and the strange premise of the mach number question in the Questions forum, seemed very odd from somebody who has 5000 hours on jets (4000 in October,) hence the confusion.

Bealzebub your obviously making good use of the Inspector Columbo series every morning on Five :ok: Iv done the same a few times and its amazing the contradictions you find on here!

Aw c'mon guys!

His age is a seemples typo - he meant 9.