ATPL GNAV theory question about relative bearing RB
Thread Starter
Joined: Jan 2020
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From: France
ATPL GNAV theory question about relative bearing RB
Hi to all, I need your help please on that question please:
A pilot spots a landmark on a relative bearing of 314°. The present compass heading is 255°, the variation is 26° W and the deviation is +2. What true bearing should be drawn from the chart to thelandmark?
001 ° 185° 005° 067° (apparently 005°) WHY?
I tried using this illustration joinded:
and a drawing but still cant find it. Many thanks!!
A pilot spots a landmark on a relative bearing of 314°. The present compass heading is 255°, the variation is 26° W and the deviation is +2. What true bearing should be drawn from the chart to thelandmark?
001 ° 185° 005° 067° (apparently 005°) WHY?
I tried using this illustration joinded:
and a drawing but still cant find it. Many thanks!!
Joined: Feb 2002
Posts: 324
Likes: 0
From: Sunny Solihull
Talk about making life difficult along with not the best worded question plus an incorrect answer (as asked).
1. Resolve C D M V T = 255+2=257-26=231 True Heading (as answer wants True)
2. TH 231+RB 314 = 545-360=185 True bearing from aircraft/chart TO the landmark, so given the wording of the question 185 is the answer not 005.
However, in a more practical application you would usually plot from a fixed position (landmark) so you would take the reciprocal 185-180=005. Protractor on landmark, draw out 005(T) the aircraft is somewhere along that line then get another bearing from another station at least 60 degrees apart draw another line & you get an approximate fix.
A word of friendly advice, when others go to the effort of answering your questions for free (like I did for Polar Stereo) it would be appreciated you at least acknowledge our efforts afterwards.
RichardH
1. Resolve C D M V T = 255+2=257-26=231 True Heading (as answer wants True)
2. TH 231+RB 314 = 545-360=185 True bearing from aircraft/chart TO the landmark, so given the wording of the question 185 is the answer not 005.
However, in a more practical application you would usually plot from a fixed position (landmark) so you would take the reciprocal 185-180=005. Protractor on landmark, draw out 005(T) the aircraft is somewhere along that line then get another bearing from another station at least 60 degrees apart draw another line & you get an approximate fix.
A word of friendly advice, when others go to the effort of answering your questions for free (like I did for Polar Stereo) it would be appreciated you at least acknowledge our efforts afterwards.
RichardH
Thread Starter
Joined: Jan 2020
Posts: 37
Likes: 0
From: France
Talk about making life difficult along with not the best worded question plus an incorrect answer (as asked).
1. Resolve C D M V T = 255+2=257-26=231 True Heading (as answer wants True)
2. TH 231+RB 314 = 545-360=185 True bearing from aircraft/chart TO the landmark, so given the wording of the question 185 is the answer not 005.
However, in a more practical application you would usually plot from a fixed position (landmark) so you would take the reciprocal 185-180=005. Protractor on landmark, draw out 005(T) the aircraft is somewhere along that line then get another bearing from another station at least 60 degrees apart draw another line & you get an approximate fix.
A word of friendly advice, when others go to the effort of answering your questions for free (like I did for Polar Stereo) it would be appreciated you at least acknowledge our efforts afterwards.
RichardH
1. Resolve C D M V T = 255+2=257-26=231 True Heading (as answer wants True)
2. TH 231+RB 314 = 545-360=185 True bearing from aircraft/chart TO the landmark, so given the wording of the question 185 is the answer not 005.
However, in a more practical application you would usually plot from a fixed position (landmark) so you would take the reciprocal 185-180=005. Protractor on landmark, draw out 005(T) the aircraft is somewhere along that line then get another bearing from another station at least 60 degrees apart draw another line & you get an approximate fix.
A word of friendly advice, when others go to the effort of answering your questions for free (like I did for Polar Stereo) it would be appreciated you at least acknowledge our efforts afterwards.
RichardH
