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Old 12th October 2011 | 21:50
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Joined: Jan 2006
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From: Europe
G-Nav question

Hi there,

I'd need some help with the following question:

The relative bearing to a beacon is 270°R. Three minutes later, at a ground speed of 180 knots, it has changed to 225°R (corrected! previously 255). What was the distance of the closest point of approach of the aircraft to the beacon?

Correct answer would be 9 nm.


I just can't figure it out at the moment (perhaps it's to late, should go to bed) - there must be a formula for this

Thanks!

Last edited by Transsonic2000; 13th October 2011 at 12:01.
Transsonic2000 is offline  
Old 13th October 2011 | 03:19
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From: NL
Are you sure the 2nd relative bearing isn't 225 degrees?
Da-20 monkey is offline  
Old 13th October 2011 | 06:47
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From: Bohol, Philippines
For 9 nm to be the correct answer the second RB would be 225R
SFI145 is offline  
Old 13th October 2011 | 11:08
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From: Hamburg
Indeed, there seems to be an error. As the others have said, the given answer of 9 nm would make the second RB 225 degrees.

The answer to the question as it is would be 36 nm (using the 1/60 rule).
hvogt is offline  
Old 13th October 2011 | 11:39
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From: London
Using trigonometry I get 33.5nm
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Old 13th October 2011 | 11:58
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From: Europe
Thanks for the respond! Yes, you guys are right, the second RB is 225 not 255 - I guess that's contributed to human error, which proofs that one should be working on this type of question when it's to late (at night)!
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