Chart question
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Joined: Nov 2006
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From: Washington
Chart question
Please help me solve this question. GSP Navigation, Chap 8
Q 8: On a transverse Mercator based on the 40E Meridian, the scale error at 80N 130E would be:
a) 1.5% too small
b) 1.5% too large
c) 0.985
d) 1.015
The correct answer give in (b), but I have no clue how to get to it.
Thanks
Q 8: On a transverse Mercator based on the 40E Meridian, the scale error at 80N 130E would be:
a) 1.5% too small
b) 1.5% too large
c) 0.985
d) 1.015
The correct answer give in (b), but I have no clue how to get to it.
Thanks
Joined: May 2005
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From: Abroad
Something's wrong there. If it's a Transverse Mercator with a prime meridian of 40E, the scale 90 degrees off at 130E is infinity [1/cos(130-40) = 1/cos(90) = 1/0].
Also, assuming a reference scale of 1.0000, answers a & c, and b & d are one and the same.
Can you check you haven't made a transcription error in your post?
Also, assuming a reference scale of 1.0000, answers a & c, and b & d are one and the same.
Can you check you haven't made a transcription error in your post?
Joined: Dec 2004
Posts: 455
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From: A place where something is or could be located; a site.
Yup. I think you'll find the question will be refering to 30E, not 130E.
Then: 1 / cos(40-30) = 1 / cos10 = 1.015
And then you get the question wrong because it asks for the ERORR. If the original scale was 1.00 (and correct) and your new scale is 1.015, then it has increase by 0.015 (the error). Which, of course, is 1.5%.
Answer (b).
EK
Then: 1 / cos(40-30) = 1 / cos10 = 1.015
And then you get the question wrong because it asks for the ERORR. If the original scale was 1.00 (and correct) and your new scale is 1.015, then it has increase by 0.015 (the error). Which, of course, is 1.5%.
Answer (b).
EK




