Math question
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Math question
hello,
I'm practising my math for the dlr test.
I've a question and i don't how to solve. I'm sure it will be easy but i don't know how to find it:
Person A and B are working together for a task and it takes 48' if they work togethr.
Person A and C are doing the same task and it takes 80 min.
Person B and C are doing the same task and it takes 60 min.
How long are A B C working?
(answer is 48min, 80min, 60min)
Can somebody tell me what calculations you have to make?
thx
I'm practising my math for the dlr test.
I've a question and i don't how to solve. I'm sure it will be easy but i don't know how to find it:
Person A and B are working together for a task and it takes 48' if they work togethr.
Person A and C are doing the same task and it takes 80 min.
Person B and C are doing the same task and it takes 60 min.
How long are A B C working?
(answer is 48min, 80min, 60min)
Can somebody tell me what calculations you have to make?
thx
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My mistake, wrong anwsers
the right answers are:
person a is 120' working
person b is 240' working
person c is 80' working
but i still don't know how to obtain this answers
anyone can help??
the right answers are:
person a is 120' working
person b is 240' working
person c is 80' working
but i still don't know how to obtain this answers
anyone can help??
Your answers are wrong.
A can solve the task in 2 hours (120 mins) working solo.
B can solve the task in 80 mins working solo.
C can solve the task in 4 hours (240 mins) solo.
As we are dealing with work being done in parallel, we need to work with reciprocal quantities, expressing the 3 task results as follows, using decimal hours throughout:
1) 1/A + 1/B = 5/4
2) 1/A + 1/C = 3/4
3) 1/B + 1/C = 1
Rearranging 3): BC = B + C => B = C / (C - 1) (call this equation X).
Subtracting 2) from 1): 1/B - 1/C = 2/4
=> C - B = 2BC/4
=> B = C - 2BC/4 => B(1 + 2C/4) = C
=> B = C / (1 + 2C/4) (call this equation Y).
Substituting eq X) in eq Y): C / (C - 1) = C / (1 + 2C/4)
Cross multiplying and cancelling: C - 1 = 1 + 2C/4
Gathering terms: 2 = C - 2C/4
=> 2 = C/2
=> C = 4 This is the first result, C takes 4 hours to complete the task.
Substituting this result in eq 3): 1/B + 1/4 = 1
=> 1/B = 3/4 => B = 4/3 hours = 80 minutes, our second result.
Substituting C = 4 in eq 2): 1/A + 1/4 = 3/4
=> 1/A = 2/4 => A = 2 hours, or 120 minutes.
So there is the complete solution, using just basic maths. I just wonder why anyone would need to work this out, and what relevance it has to commercial aviation, especially as it cannot be worked out quickly on the back of a fag packet whilst flying!
It is also quite worrying that even the published solutions are wrong. Maybe the originator of the question ought to return to being the student rather than the teacher / examiner!!
A can solve the task in 2 hours (120 mins) working solo.
B can solve the task in 80 mins working solo.
C can solve the task in 4 hours (240 mins) solo.
As we are dealing with work being done in parallel, we need to work with reciprocal quantities, expressing the 3 task results as follows, using decimal hours throughout:
1) 1/A + 1/B = 5/4
2) 1/A + 1/C = 3/4
3) 1/B + 1/C = 1
Rearranging 3): BC = B + C => B = C / (C - 1) (call this equation X).
Subtracting 2) from 1): 1/B - 1/C = 2/4
=> C - B = 2BC/4
=> B = C - 2BC/4 => B(1 + 2C/4) = C
=> B = C / (1 + 2C/4) (call this equation Y).
Substituting eq X) in eq Y): C / (C - 1) = C / (1 + 2C/4)
Cross multiplying and cancelling: C - 1 = 1 + 2C/4
Gathering terms: 2 = C - 2C/4
=> 2 = C/2
=> C = 4 This is the first result, C takes 4 hours to complete the task.
Substituting this result in eq 3): 1/B + 1/4 = 1
=> 1/B = 3/4 => B = 4/3 hours = 80 minutes, our second result.
Substituting C = 4 in eq 2): 1/A + 1/4 = 3/4
=> 1/A = 2/4 => A = 2 hours, or 120 minutes.
So there is the complete solution, using just basic maths. I just wonder why anyone would need to work this out, and what relevance it has to commercial aviation, especially as it cannot be worked out quickly on the back of a fag packet whilst flying!
It is also quite worrying that even the published solutions are wrong. Maybe the originator of the question ought to return to being the student rather than the teacher / examiner!!
Last edited by pilotmike; 21st Feb 2008 at 15:12.
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Captain djaffar,
the answers I gave above are not out of logic....It is that you didn't hear so far about the reductibility of equations....very simple!
the answers I gave above are not out of logic....It is that you didn't hear so far about the reductibility of equations....very simple!
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ayy ayy inner
i didnt notice the hour unit.had the problem too quickly.
that's why i did not take it in consideration.
but based on a purely equational assumption like i did as well as A13 the results 34,14,46 are perfect.
but accounting for the hour factor 'complicates' the whole matter...and your question ask to take it into account...
pilotmike..cheeeeeeeeeeeeers
that's why i did not take it in consideration.
but based on a purely equational assumption like i did as well as A13 the results 34,14,46 are perfect.
but accounting for the hour factor 'complicates' the whole matter...and your question ask to take it into account...
pilotmike..cheeeeeeeeeeeeers
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Looks very complicated...
I have seen simpler questions on aptitude tests along the lines of:
If John completes 5 tasks in 27 minutes and Bob completes 5 tasks in 54 minutes, how long will it take them to complete 5 tasks if they work together?
But never anything so complex as the question above!
Bri
The answer to the above is 18 (apparently!)
If John completes 5 tasks in 27 minutes and Bob completes 5 tasks in 54 minutes, how long will it take them to complete 5 tasks if they work together?
But never anything so complex as the question above!
Bri
The answer to the above is 18 (apparently!)
Again, Captain_djaffar is mistaken. It has nothing to do with having 1 hour wrong either - that is simply a red herring, of no relevance.
Trying to convince us that
is simply pointless. The results are simply WRONG, and therefore far from perfect.
You simply cannot say that if two people, A and B take 48 minutes to complete a task, then each of them take LESS time to complete it individually. (airman13 would like us to believe that A takes 34 minutes and B takes 14 minutes to do the task individually, therefore they take a total of 48 minutes when working together). Life just doesn't work like that! Take a closer at my earlier dripping tap example to prove it.
This really doesn't warrant further discussion, as you are not accepting the principle that working individually takes longer than working together, as in the tap example.
I notice that your earlier post with incorrect calculations has mysterioulsy disappeared from this thread now!
Simply, inner asked to be shown the calculation needed, and after receiving some wild guesses which were wrong, I offered him the correct and complete solution in post #6, which your deleted post now has made post #5.
PM
Trying to convince us that
the results 34,14,46 are perfect
You simply cannot say that if two people, A and B take 48 minutes to complete a task, then each of them take LESS time to complete it individually. (airman13 would like us to believe that A takes 34 minutes and B takes 14 minutes to do the task individually, therefore they take a total of 48 minutes when working together). Life just doesn't work like that! Take a closer at my earlier dripping tap example to prove it.
This really doesn't warrant further discussion, as you are not accepting the principle that working individually takes longer than working together, as in the tap example.
I notice that your earlier post with incorrect calculations has mysterioulsy disappeared from this thread now!
Simply, inner asked to be shown the calculation needed, and after receiving some wild guesses which were wrong, I offered him the correct and complete solution in post #6, which your deleted post now has made post #5.
PM
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ohey pilotmike
i understand ur point pilotmickey...i said the answers are perfect if they represent a simple equation and not involving the factor of time...which i did by mistake....which by the way doesnt solve inner's problem!Perfect only for another problem with mere units rather than hours.
your answer is perfectly descriptive of the real problem and gives the real solution.
happy?
really it was good explanation and indeed rather tough for an aptitude test.
maybe more suitable for a cambridge Thinking skill 3th paper....
your answer is perfectly descriptive of the real problem and gives the real solution.
happy?
really it was good explanation and indeed rather tough for an aptitude test.
maybe more suitable for a cambridge Thinking skill 3th paper....
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it is a harder version of the basic simultaneous equations/system of equation, done at O/standard grade maths level.
i hope the big red sentence at the bottom of the page isnt taking effect here as many pilots/engineers/ numerically orientated people on here may end up getting a bit embaressed.
i hope the big red sentence at the bottom of the page isnt taking effect here as many pilots/engineers/ numerically orientated people on here may end up getting a bit embaressed.
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There are some interesting interpretations in this string.
But I think that we need to RTFQ.
The question did not ask how long it would take each individual to complete the task when working alone.
It asked "How long are A B C working?"
Nothing in the question suggests that any individual works less than the full specified time when part of a specified pair.
A works with B for 48 minutes and with C for 80 minutes. So A works for a total of 48 + 80 = 128 minutes.
B works with A for 48 minutes and with C for 60 minutes. So B works for 48 + 60 = 108 minutes.
C works with B for 60 minutes and with A for 80 minutes. So C works for 60 + 80 = 140 minutes.
"Words failurise me" ................................. George Dubbya Bush.
"Don't let them failurise you"................... RTFQ.
But I think that we need to RTFQ.
The question did not ask how long it would take each individual to complete the task when working alone.
It asked "How long are A B C working?"
Nothing in the question suggests that any individual works less than the full specified time when part of a specified pair.
A works with B for 48 minutes and with C for 80 minutes. So A works for a total of 48 + 80 = 128 minutes.
B works with A for 48 minutes and with C for 60 minutes. So B works for 48 + 60 = 108 minutes.
C works with B for 60 minutes and with A for 80 minutes. So C works for 60 + 80 = 140 minutes.
"Words failurise me" ................................. George Dubbya Bush.
"Don't let them failurise you"................... RTFQ.
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Oh ****! is anyone else reading this realising that maths is a very weak point of theirs like i am. Why cant we all just get jobs on flying skills alone (sigh)
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If they were French, then the answer is a lot easier.
They weren't working at all but on strike or reading the newspaper, or actually off doing a little job on the 'noir'....and having a friend X clock them in and out.
So the answer for A B C is Zero... (that's if they're French).
They weren't working at all but on strike or reading the newspaper, or actually off doing a little job on the 'noir'....and having a friend X clock them in and out.
So the answer for A B C is Zero... (that's if they're French).
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Originally Posted by pilotmike
This question is again about tasks completed in parallel, so reciprocals are required. Working in minutes this time, for convenience, the equation is:
B
It reminds me when elecrical resistors are in parallel: there you have to use reciprocals (for the same reasons) too.
How does any of this help you to fly a plane ?
But inner simply wanted help with seeing how to solve the problem, so I obliged.
PM
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Help me I cant stand It!!!
I sit here every other night or so just quietly checking out what my peers are up to and saying nothing but this is too much.
The question is rubbish, its not really a problem, who asked it, I want to kick them in the shins! And the answer is b
s! and if its part of the problem its not clever it just becomes an illogical problem or bigger bs
Person A works for 48 mins with B and 80 mins with C = 128 mins!
Person B works for 48 mins with A and 60 mins with C = 108 mins!!
Person C works for 80 mins with A and 60 mins with B = 140 mins!!!
Question: How long are A B C working?
A+B+C= 376 mins. or to be really clever
6 hrs and 16 mins.
Kieth I salute you.
Pilot mike I salute you also, the force is strong with you but WOOD FOR TREES
I sit here every other night or so just quietly checking out what my peers are up to and saying nothing but this is too much.
The question is rubbish, its not really a problem, who asked it, I want to kick them in the shins! And the answer is b
s! and if its part of the problem its not clever it just becomes an illogical problem or bigger bsPerson A works for 48 mins with B and 80 mins with C = 128 mins!
Person B works for 48 mins with A and 60 mins with C = 108 mins!!
Person C works for 80 mins with A and 60 mins with B = 140 mins!!!
Question: How long are A B C working?
A+B+C= 376 mins. or to be really clever
6 hrs and 16 mins.Kieth I salute you.
Pilot mike I salute you also, the force is strong with you but WOOD FOR TREES
Pilot mike I salute you also, the force is strong with you but WOOD FOR TREES
PM
Last edited by pilotmike; 21st Feb 2008 at 15:18.
but the obvious question is, what sort of job are they doing?
Are they UK council workers because if so, there's no way they would work that long and furthermore, there'd be twice as many workers doing half as much work, taking into account the two 'workers' who satnd and watch the proceedings!
PS, I'm s**t at maths.
Are they UK council workers because if so, there's no way they would work that long and furthermore, there'd be twice as many workers doing half as much work, taking into account the two 'workers' who satnd and watch the proceedings!
PS, I'm s**t at maths.