Ground School Exam Questions & Question Banks
Join Date: Oct 2005
Location: panama
Posts: 403
Likes: 0
Received 0 Likes
on
0 Posts
ATPL question bank
hello all,
is there any website providing a free/trial ATPL question bank? I've had a look on this >> http://213.48.96.23/atponline/jalo/index.asp but it only offers a demo version, the full one costs 72euros.. The latest version is the CQB 10 at the moment, I assume.
thank you in advance!
is there any website providing a free/trial ATPL question bank? I've had a look on this >> http://213.48.96.23/atponline/jalo/index.asp but it only offers a demo version, the full one costs 72euros.. The latest version is the CQB 10 at the moment, I assume.
thank you in advance!
Join Date: May 2003
Location: uk
Posts: 713
Likes: 0
Received 0 Likes
on
0 Posts
Now why should anyone make available a free question bank? - no the one you have seen the demo of is the best around and if you dont want to pay all of €70 can you afford to do the exams in the first place?.
Join Date: Aug 2005
Location: England
Posts: 149
Likes: 0
Received 0 Likes
on
0 Posts
Use Bristol Groundschool, and you'll get everything you need from the guys there. I am a moron and passed all 14 on first attempt. The system is so fine tuned it's near impossible to be unsuccessful.
Super-Friendly Aviator
Join Date: Jun 2004
Location: Reigate, UK
Age: 42
Posts: 424
Likes: 0
Received 0 Likes
on
0 Posts
Wangus is right. BGS's online bank is the way forward. What's £50 in the grand scheme of things? Especially if it more or less guarantees you good marks...
Join Date: Oct 2005
Location: panama
Posts: 403
Likes: 0
Received 0 Likes
on
0 Posts
constant of the cone calculaton
hello guys,
what method do you apply when you calculate the constant of the cone on a Lambert conformal conic chart?
thx
PS: the query about the free database didn't have any great importance since I'm already using the CQB10 Cd-rom provided by my FTO. I only intended to look for another database and see if there were any new questions, but it's not such a big issue. Thank you anyway
what method do you apply when you calculate the constant of the cone on a Lambert conformal conic chart?
thx
PS: the query about the free database didn't have any great importance since I'm already using the CQB10 Cd-rom provided by my FTO. I only intended to look for another database and see if there were any new questions, but it's not such a big issue. Thank you anyway
Join Date: Sep 2006
Location: milton keynes
Age: 38
Posts: 4
Likes: 0
Received 0 Likes
on
0 Posts
lamberts
As far as i remember you get the constant of the cone from:
Sine PO
PO= parallel of origin
This relates to convergence which is ch long x sine po
Hope i have remembered correctly it has been a while
Sine PO
PO= parallel of origin
This relates to convergence which is ch long x sine po
Hope i have remembered correctly it has been a while
Join Date: Oct 2005
Location: panama
Posts: 403
Likes: 0
Received 0 Likes
on
0 Posts
i think it's not the correct calculation, because I've to answer a question where the standard parallels are 07°40'N and 38°20'N.
The constant of the cone is then: 0,39 0,6 0,92 or 0,42?
The constant of the cone is then: 0,39 0,6 0,92 or 0,42?
Join Date: Sep 2006
Location: milton keynes
Age: 38
Posts: 4
Likes: 0
Received 0 Likes
on
0 Posts
lamberts
The answer to the question should be .39 then??
If your standard parallels are 7.40 N and 38.20 N then your parallel of origin is 23 degrees north.
Sine x 23 = 0.39
If your standard parallels are 7.40 N and 38.20 N then your parallel of origin is 23 degrees north.
Sine x 23 = 0.39
Join Date: May 2006
Location: UK
Posts: 202
Likes: 0
Received 0 Likes
on
0 Posts
P.o.f Atpl Question
Hi Guys,
Need help with a Pof Question, I'm sure it's just me and the answer is simple? here goes:
An A/C is in a level turn, at a constant TAS of 300Kts and a bank angle of 45 degrees. It's turning radius is:
A, 9000
B, 2381
C, 3354
D, 4743
The answer is B, How the hell do you get to that answer?
Your help is much appreciated.
Cheers
Dan
Need help with a Pof Question, I'm sure it's just me and the answer is simple? here goes:
An A/C is in a level turn, at a constant TAS of 300Kts and a bank angle of 45 degrees. It's turning radius is:
A, 9000
B, 2381
C, 3354
D, 4743
The answer is B, How the hell do you get to that answer?
Your help is much appreciated.
Cheers
Dan
Join Date: Sep 2003
Location: Down under
Posts: 11
Likes: 0
Received 0 Likes
on
0 Posts
Probably you know the formula:
r = V square / (11.26 * TAN angle) with V in kt and r in feet
Gives you 7992.9 feet as radius = 2436.23592 meters. Best answer is therfore B.
Hope it helps
r = V square / (11.26 * TAN angle) with V in kt and r in feet
Gives you 7992.9 feet as radius = 2436.23592 meters. Best answer is therfore B.
Hope it helps
Join Date: Aug 2001
Location: Dorset
Posts: 775
Likes: 0
Received 0 Likes
on
0 Posts
An A/C is in a level turn, at a constant TAS of 300Kts and a bank angle of 45 degrees. It's turning radius is:
A, 9000
B, 2381
C, 3354
D, 4743
The equation that you require is:
Turn Radius = V squared / gTanAOB
To get radius in meters you need to convert the TAS from Kts into m/sec by multiplying it by 0.515
If you use g = 10 m/sec squared this gives:
Radius = (300 x 0.51)squared / (10 x TAN 45)
Radius = 2387 m
This is closest to option B.
A, 9000
B, 2381
C, 3354
D, 4743
The equation that you require is:
Turn Radius = V squared / gTanAOB
To get radius in meters you need to convert the TAS from Kts into m/sec by multiplying it by 0.515
If you use g = 10 m/sec squared this gives:
Radius = (300 x 0.51)squared / (10 x TAN 45)
Radius = 2387 m
This is closest to option B.
Guest
Posts: n/a
Danny
Equation for this stuff is tan(bank angle)=(speed^2)/(g*radius)
Re-arrange to get radius=(speed^2)/(g*tan(bank angle))
Speed must be in m/s to get answer in m. Use g=10; tan(45) =1. I then get 2385m (TAS in knots should be halved roughly to get m/s)
I can't remember now what's in my ATPL pof notes (I didn't really read them; I've got a PhD in Aeronautics which gave me the ability to do the exam without reading the notes!)
ATPL notes may give it in a different way, but the equation above will never fail you. Oh, and from my experience the question bank never uses angles other than 45 deg, so tan(bank angle) will always be 1.
Jings - all those replies at once. Mine's redundant!
Equation for this stuff is tan(bank angle)=(speed^2)/(g*radius)
Re-arrange to get radius=(speed^2)/(g*tan(bank angle))
Speed must be in m/s to get answer in m. Use g=10; tan(45) =1. I then get 2385m (TAS in knots should be halved roughly to get m/s)
I can't remember now what's in my ATPL pof notes (I didn't really read them; I've got a PhD in Aeronautics which gave me the ability to do the exam without reading the notes!)
ATPL notes may give it in a different way, but the equation above will never fail you. Oh, and from my experience the question bank never uses angles other than 45 deg, so tan(bank angle) will always be 1.
Jings - all those replies at once. Mine's redundant!
Last edited by 'India-Mike; 23rd Apr 2007 at 18:58. Reason: Other, quicker replies!
Join Date: May 2006
Location: Essex
Age: 40
Posts: 5
Likes: 0
Received 0 Likes
on
0 Posts
Hi,
unless someone corrects me its somethings like.........
Radius = Vsquared / GxTan angle of bank
V squared is TAS converted from Knots into metres then squared, conversion factor is 0.514 approx. G = load factor, use 10.
therefore
Radius = (300squared x 0.514 ) / 10 x tan 45deg. = 2377
closest answer 2381.
good luck
paul
unless someone corrects me its somethings like.........
Radius = Vsquared / GxTan angle of bank
V squared is TAS converted from Knots into metres then squared, conversion factor is 0.514 approx. G = load factor, use 10.
therefore
Radius = (300squared x 0.514 ) / 10 x tan 45deg. = 2377
closest answer 2381.
good luck
paul
Join Date: Oct 2006
Location: EGBJ Gloucester
Age: 40
Posts: 103
Likes: 0
Received 0 Likes
on
0 Posts
Winds aloft calculation help needed
1Hi all.
Just running through PPL confuser for Nav exam, come across a question (number 41 too ) that I can't get one of the provided choices for!
I've had no problem with the others but I'd be really grateful if someone could just check my answer.
The question is given: heading = 138(T), track = 141(T), TAS = 122kt, GS = 101kt, find w/v.
I get 124/22 consistently, according to the book the answer is 131/21
Thanks in advance!
Rob
Just running through PPL confuser for Nav exam, come across a question (number 41 too ) that I can't get one of the provided choices for!
I've had no problem with the others but I'd be really grateful if someone could just check my answer.
The question is given: heading = 138(T), track = 141(T), TAS = 122kt, GS = 101kt, find w/v.
I get 124/22 consistently, according to the book the answer is 131/21
Thanks in advance!
Rob