Wikiposts
Search
Professional Pilot Training (includes ground studies) A forum for those on the steep path to that coveted professional licence. Whether studying for the written exams, training for the flight tests or building experience here's where you can hang out.

Need answer of this

Thread Tools
 
Search this Thread
 
Old 7th Jun 2006, 14:24
  #1 (permalink)  
Thread Starter
 
Join Date: Jun 2006
Location: USA
Posts: 12
Likes: 0
Received 0 Likes on 0 Posts
Question Need answer of this

Hi is anybody can solve this
An aircraft flies the following true RL tracks and distance in NM in succession
000 deg. 600 nm 090 deg 800 nm 180 deg.600 nm 270deg 800 nm
and arrives back at its starting place. The latitude of the starting point must be.
85 deg. N / 85 deg S / 5 deg S / 5 deg N

thanks
sunny5679 is offline  
Old 7th Jun 2006, 16:10
  #2 (permalink)  
 
Join Date: Nov 2003
Location: Westward TV
Posts: 412
Likes: 0
Received 0 Likes on 0 Posts
5 degree south. the trick is to make sure that the flights east and west are on the same relative latitude.
GusHoneybun is offline  
Old 8th Jun 2006, 15:54
  #3 (permalink)  
Thread Starter
 
Join Date: Jun 2006
Location: USA
Posts: 12
Likes: 0
Received 0 Likes on 0 Posts
thanks

thanks for this answer, but i do not understand why it is 5 deg south.because in the question, asking the latitude of the starting point,
and the starting point is 000 deg. i think it should be 5 deg. North .please let me if i am correct.
thanks
sunny
sunny5679 is offline  
Old 8th Jun 2006, 18:10
  #4 (permalink)  
PPRuNe Supporter
 
Join Date: Aug 2005
Location: DXB
Posts: 31
Likes: 0
Received 0 Likes on 0 Posts
I agree with the Gus feller - if you start off with a track of 000 or 360 then you're going North, and if you are going to have equivalent latitudes for the east/west legs then you need to cross the equator half way through that 600nm leg. So you need to start at 5S.

Cheers,

SB
SILENT_BADGER is offline  
Old 9th Jun 2006, 07:08
  #5 (permalink)  
 
Join Date: Aug 2001
Location: Dorset
Posts: 775
Likes: 0
Received 0 Likes on 0 Posts
To understand this problem you must take two factors into account:

1. The meridians diverge as you move towards the equator and converge as you move away from it.

2. If you move the same distance north, then south, then east, then west,
your end point will depend upon the relative magnitudes of any convergence or divergence which occur. You will end up at your starting point only if the diveregnce/convergence going north is exactly equal and opposite to the divergence/convergence going south.

This question specifies 600 nm. Each minute of arc on a meridian is one nm, so 600 nm is 10 degrees.

If you are 5 degrees south of the equator and start by going 600 nm (or 10 degrees) north you will get divergence over the first 5 degrees (up to the equator). You will then get the same amount of convergence over the next 5 degrees, as you move away from the equator. So the overall efect of the convergence/divergnce will be zero.

The same will happen during the southerly leg of the journey. So you would end up back where you started.

If you now look at the efects of starting at 85 north or south, you will see that this self-cancelling effect does not occur.
Keith.Williams. is offline  
Old 10th Jun 2006, 06:01
  #6 (permalink)  
Thread Starter
 
Join Date: Jun 2006
Location: USA
Posts: 12
Likes: 0
Received 0 Likes on 0 Posts
thanks

thanks for this explaination. now i understand.
sunny5679 is offline  

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Trackbacks are Off
Pingbacks are Off
Refbacks are Off



Contact Us - Archive - Advertising - Cookie Policy - Privacy Statement - Terms of Service

Copyright © 2024 MH Sub I, LLC dba Internet Brands. All rights reserved. Use of this site indicates your consent to the Terms of Use.