Mercator scale question
Thread Starter
Joined: Jan 2004
Posts: 159
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From: UK
Mercator scale question
Hi,
Having trouble with this one,
'On a mercator chart the distance between two meridians 1deg apart is 7.45cm. What is the scale at 48degN?'
Now, I came out with the answer 1:491,543 = 1:500,000
However the answer given is 1:1000,000?
I worked it out by: 1deg = 60nm so 60nm =7.45cm
60nm = 11112000cm so, divide that by 7.45 and you get 1:1491543.
I just cant see how it could be 1:1000,000?
If anyone could shed some light that would be great.
Thanks
Foz
Having trouble with this one,
'On a mercator chart the distance between two meridians 1deg apart is 7.45cm. What is the scale at 48degN?'
Now, I came out with the answer 1:491,543 = 1:500,000
However the answer given is 1:1000,000?
I worked it out by: 1deg = 60nm so 60nm =7.45cm
60nm = 11112000cm so, divide that by 7.45 and you get 1:1491543.
I just cant see how it could be 1:1000,000?
If anyone could shed some light that would be great.
Thanks
Foz
Joined: Dec 2003
Posts: 339
Likes: 0
From: Derby
Well
Only way to get 1:1.000.000 is by using
Dep= 60xCos48= 40 NM which is74080 meters or 7408000 cm.
CL/ED = 7.45/ 7408000 = 0.000001005669
or if you prefer= 994362.4161 which is a darn sight close to 1.000.000 and therefore it must be 1:1.000.000
Dep= 60xCos48= 40 NM which is74080 meters or 7408000 cm.
CL/ED = 7.45/ 7408000 = 0.000001005669
or if you prefer= 994362.4161 which is a darn sight close to 1.000.000 and therefore it must be 1:1.000.000
Joined: Nov 2001
Posts: 60
Likes: 0
From: London
Aim High
'On a mercator chart the distance between two meridians 1deg apart is 7.45cm. What is the scale at 48degN?'
The distance between the two meridians is at 48 N is found by departure formula:
Dep (in NM) = dlong in min x cos mlat
Dep (in NM) = (1 x 60 x cos 48)
Dep (in NM) = 40.147836381
1 / d = CL / ED
1 / d = 7.45 cm / 7435379.29785963 cm
d = 991383.9 (approximately 1,000,000)
The scale at the Equator could also be found if requested
Since on a std Mercator scale expands as a function of secant lat
secant lat = 1 / cos lat
New d / Old d = Old secant lat / New secant lat
Must rush dinner on table (lol)
The distance between the two meridians is at 48 N is found by departure formula:
Dep (in NM) = dlong in min x cos mlat
Dep (in NM) = (1 x 60 x cos 48)
Dep (in NM) = 40.147836381
1 / d = CL / ED
1 / d = 7.45 cm / 7435379.29785963 cm
d = 991383.9 (approximately 1,000,000)
The scale at the Equator could also be found if requested
Since on a std Mercator scale expands as a function of secant lat
secant lat = 1 / cos lat
New d / Old d = Old secant lat / New secant lat
Must rush dinner on table (lol)




