Norwegian new seats 16.8 inches wide!?!?!

[krismiler]

These extra narrow seats are bulkhead seats which have extra legroom and are normally sold at a premium price. The regular seats are slightly wider but have reduced legroom so either way you lose, but personally I would prefer the extra legroom and easier access.

[DaveReidUK]

Originally Posted by underfire

Delta seat widths per ac...https://www.delta.com/content/www/en_US/traveling-with-us/airports-and-aircraft/Aircraft/boeing-737-900er-739.htmlI
You must also check where the measurement is from. Some use center of armrest to center, others use distance between armrests

I think it's pretty universal to quote "seat width" as the measurement between the inside faces of the armrests, as per B ("pax width") in the diagram.

The distance between the centres of the armrests, somewhat disingenuously described in the diagram as "hip clearance" (typically 2 inches more than B for a Y seat) only becomes relevant if you're having an armrest war with the passenger next to you.

[Gilmorrie]

There is something that puzzles me about these seat dimensions. Let's assume, for discussion, the spacing between the insides of the armrests is 16.8 in. So, 16.8 x pi = 52.8 in, which means that a spherical or cylindrical shape of that circumference would just fit, but barely. The central portion of my torso isn't exactly spherical or cylindrical, but even being a bit overweight, it is nowhere near 52.8 in, circumference. (My waist size in 38 in., and my hips measure 43 in. I am a male, 5ft-11in, 190 lb.)

[Lascaille]

Originally Posted by Gilmorrie

There is something that puzzles me about these seat dimensions. Let's assume, for discussion, the spacing between the insides of the armrests is 16.8 in. So, 16.8 x pi = 52.8 in, which means that a spherical or cylindrical shape of that circumference would just fit, but barely. The central portion of my torso isn't exactly spherical or cylindrical, but even being a bit overweight, it is nowhere near 52.8 in, circumference. (My waist size in 38 in., and my hips measure 43 in. I am a male, 5ft-11in, 190 lb.)

And your body at your waist or hips is probably at least three times as wide as it is deep.

If we assume that exact ratio we can model the cross-section of your hips as a rectangle of width 3x and depth 1x, with a total perimeter of 8x. If we shove in the figure for your hips we get 43" / 8x = means x = 5.375. Width is 3x so 5.375 x 3 = 16.125". Congratulations, you fit.