Aerodynamicists Question
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Aerodynamicists Question
Here is a question that I hope someone can answer.
Let's say you had a current MTOW of 1,000 kg's with a stall speed of 50 knots. Easy round figures to start with.
You somehow lower the stall speed of the aircraft, eg. wing extension, wing-tips, vortex generators, flap modification etc. As a result you have lowered the stall speed by 5 knots, to 45 knots.
I then need to work out what the weight needs to be to stall the aircraft back at 50 knots.
Eg., 1,200 kg's.
This is probably not possible and I realise flight testing would be a good start but it would be good to start with some numbers to work back from.
Let's say you had a current MTOW of 1,000 kg's with a stall speed of 50 knots. Easy round figures to start with.
You somehow lower the stall speed of the aircraft, eg. wing extension, wing-tips, vortex generators, flap modification etc. As a result you have lowered the stall speed by 5 knots, to 45 knots.
I then need to work out what the weight needs to be to stall the aircraft back at 50 knots.
Eg., 1,200 kg's.
This is probably not possible and I realise flight testing would be a good start but it would be good to start with some numbers to work back from.
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L=1/2. ρ.V^2 .S.Cl
In this instance, ρ and S (density and reference area) remain constant, by making the aerodynamic addition you are increasing the Cl at which stall occurs.
If the new stall speed is 45kts (23.2 m/s) at 1000kg mass (weight of 9800 N), then the new Cl (the Cl at which stall occurs) can be found (along with the constants ρ and S)
1/2.ρ.S.Cl=L/V^2
= 9800/(23.2^2)
= 18.3
Then the lift at a speed of 50kts (25.7m/s) can be found as well.
L=(1/2. ρ .S.Cl).V^2
= (18.3) . 25.7^2
= 12087 N
This is equal to a mass of 1233kg.
In this instance, ρ and S (density and reference area) remain constant, by making the aerodynamic addition you are increasing the Cl at which stall occurs.
If the new stall speed is 45kts (23.2 m/s) at 1000kg mass (weight of 9800 N), then the new Cl (the Cl at which stall occurs) can be found (along with the constants ρ and S)
1/2.ρ.S.Cl=L/V^2
= 9800/(23.2^2)
= 18.3
Then the lift at a speed of 50kts (25.7m/s) can be found as well.
L=(1/2. ρ .S.Cl).V^2
= (18.3) . 25.7^2
= 12087 N
This is equal to a mass of 1233kg.
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.. or, if you want to do it without any brain strain -
Recalling that
(a) at the stall, CL = CLmax and is presumed to be constant
(b) L = W, if we make the dubious presumption of level flight
Then, where "1" indicates before, and "2" after ..
CLmax = L1/(1/2.rho.V1^2.S) = L2/(1/2.rho.V2^2.S)
so, cancelling out the common factors
W1/V1^2 = W2/V2^2
from which you get either
V2 = V1.sqrt(W2/W1), or
W2 = W1.(V2/V1)^2
So, with the example figures given, and presuming that the speeds are CAS, not IAS
W2 = 1000.(50/45)^2 = 1234.6 (call it 1235)
This only has some validity for a constant configuration comparison.
Also, and this is very important, PEC gets interesting around the stall so IAS won't hack it (we've all seen a Cessna with naught on the clock at the stall - means nothing due to PEC) so you have to do the sums in CAS to get anything in the way of sense out of the sums.
I think that this was where Matt was coming from ?
Recalling that
(a) at the stall, CL = CLmax and is presumed to be constant
(b) L = W, if we make the dubious presumption of level flight
Then, where "1" indicates before, and "2" after ..
CLmax = L1/(1/2.rho.V1^2.S) = L2/(1/2.rho.V2^2.S)
so, cancelling out the common factors
W1/V1^2 = W2/V2^2
from which you get either
V2 = V1.sqrt(W2/W1), or
W2 = W1.(V2/V1)^2
So, with the example figures given, and presuming that the speeds are CAS, not IAS
W2 = 1000.(50/45)^2 = 1234.6 (call it 1235)
This only has some validity for a constant configuration comparison.
Also, and this is very important, PEC gets interesting around the stall so IAS won't hack it (we've all seen a Cessna with naught on the clock at the stall - means nothing due to PEC) so you have to do the sums in CAS to get anything in the way of sense out of the sums.
I think that this was where Matt was coming from ?
It would appear that The Green Goblin attended a different uni and/or PoF lectures at the flying school to most of us ?
A consequence of being to 'heavy' is exceeding the critical abgle by attempting to generate additional lift which results in a stall.
So therein lies your answer!
As a result you have lowered the stall speed by 5 knots, to 45 knots.
It would appear that The Green Goblin attended a different uni and/or PoF lectures at the flying school to most of us ?
A stall occurs not when you go below the stall speed, but when you exceed the critical angle.
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A stall occurs not when you go below the stall speed, but when you exceed the critical angle.
There is some validity in that but the posters miss the thrust of the thread. A bit like saying "the sky is blue" which doesn't give any information as to the what, when, how or why.
Either way, and all jokes aside, I really do suggest that you both revisit the books and then go ask for your money back from whomever did your initial principles of flight instruction - coz either you wuz ripped orf or weren't paying all that much attention
... we are talking flow angles in terms of the parameters which affect the indirect measurement of those angles.
Mr McDonal doesn't indicate which airline it is for which he flies. You have the option of asking your ops engineering section to run over the engineering again for your interest. I am quite sure that they will opt for a variation on your story.
There is some validity in that but the posters miss the thrust of the thread. A bit like saying "the sky is blue" which doesn't give any information as to the what, when, how or why.
Either way, and all jokes aside, I really do suggest that you both revisit the books and then go ask for your money back from whomever did your initial principles of flight instruction - coz either you wuz ripped orf or weren't paying all that much attention
... we are talking flow angles in terms of the parameters which affect the indirect measurement of those angles.
Mr McDonal doesn't indicate which airline it is for which he flies. You have the option of asking your ops engineering section to run over the engineering again for your interest. I am quite sure that they will opt for a variation on your story.
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From the said manual, page 33;
RELATIONSHIP BETWEEN CRITICAL ANGLE AND STALLING SPEED
Explain that for a given weight at ‘1’ g every angle of attack including the critical angle, has its associated indicated airspeed. As the angle of attack of the wings invariably cannot be observed, reference is therefore made to an aeroplane’s stalling speed.
FACTORS AFFECTING THE STALLING SPEED
The basic stalling speed of an aeroplane, such as referred
to in an Operations Manual or Owner’s Handbook means
the indicated airspeed at which the aeroplane will stall
from straight and level flight, with power off.
Explain that the stalling speed will vary, depending on:
(a) Weight
(b) Power
(c) Flap and/or Slat position
(d) Manoeuvre
(e) Ice on or damage to wings
Last edited by training wheels; 16th Sep 2009 at 11:28.
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I love it. Green Goblin & rmcdonal (who?) correcting Mr Tullamarine on a point of P of F. Can't work out whether it's funny or tragic. But it's certainly priceless, either way.
As the angle of attack of the wings invariably cannot be observed, reference is therefore made to an aeroplane’s stalling speed."
Come on guy's! I can't believe something so trivial as this is causing such confusion!
This is why 'stalling speed' is so en grained in peoples collective thoughts. As an instructors we teach the lesson on stalling by demonstrating it with a decreasing airspeed. Don't forget when we demonstrate stalling we get you to look out the window at the increasing angle of attack relative to the horizon.
You can stall at high speed, you can stall at low speed, you stall anytime you exceed the critical angle of attack.
Vs is simply the minimum steady flight speed. Reduce the airspeed anymore and you will need to increase the angle of attack to generate more lift. Increase the angle of attack anymore and you will stall.
Either way, and all jokes aside, I really do suggest that you both revisit the books and then go ask for your money back from whomever did your initial principles of flight instruction - coz either you wuz ripped orf or weren't paying all that much attention
... we are talking flow angles in terms of the parameters which affect the indirect measurement of those angles.
... we are talking flow angles in terms of the parameters which affect the indirect measurement of those angles.
FACTORS AFFECTING THE STALLING SPEED
The basic stalling speed of an aeroplane, such as referred
to in an Operations Manual or Owner’s Handbook means
the indicated airspeed at which the aeroplane will stall
from straight and level flight, with power off.
Explain that the stalling speed will vary, depending on:
(a) Weight
(b) Power
(c) Flap and/or Slat position
(d) Manoeuvre
(e) Ice on or damage to wings
The basic stalling speed of an aeroplane, such as referred
to in an Operations Manual or Owner’s Handbook means
the indicated airspeed at which the aeroplane will stall
from straight and level flight, with power off.
Explain that the stalling speed will vary, depending on:
(a) Weight
(b) Power
(c) Flap and/or Slat position
(d) Manoeuvre
(e) Ice on or damage to wings
I'm still struggling to comprehend how smart people get something so simple, so wrong!
Last edited by The Green Goblin; 16th Sep 2009 at 11:39.
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Goblin.....you are a **** stirrer...though correct....love it.
A stall can happen at any old time. Just pull the stick, exceed critical angle, hey presto....stalled aerofoil.
A stall can happen at any old time. Just pull the stick, exceed critical angle, hey presto....stalled aerofoil.
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Of course another consideration is that
L=1/2. ρ.V^2 .S.Cl
is an oversimplification/half truth/something/certainly not worth too many significant figures.
Cl varies with Reynolds number ie with rho, V and chord (a big compnent of S) and that variation is different for different airfoils.
Now if the reduction in stall speed is achieved with wing extension then we have a change in aspect ratio; whole new sets of things to play with.
L=1/2. ρ.V^2 .S.Cl
is an oversimplification/half truth/something/certainly not worth too many significant figures.
Cl varies with Reynolds number ie with rho, V and chord (a big compnent of S) and that variation is different for different airfoils.
Now if the reduction in stall speed is achieved with wing extension then we have a change in aspect ratio; whole new sets of things to play with.