Aptitude Questions

[departandarrive]

1. Your travelling at 240kts. How far will you travel in 4 hours and 20 mins?



2. You establish on the ILS at 9 miles. What height would you expect to be?




3. You are travelling at 250 kts, and are at FL250. The procedure starts at 3000ft QNH. Where is the Top Of Descent Point?




If aircraft A took of at 10am flying at 170 mph and aircraft B took of at 10.45am flying at 230 mph. When would they meet and how far would they have travelled?

Va (Speed of Aircraft A) = 170 mph
Vb (Speed of Aircraft B) = 230 mph
Departure time of A: 10:00
Departure time of A: 10:45
45 minutes = 0.75 hours


After 45 minutes Distance travelled by Aircraft A: D = Va x 45 minutes = 170 x 0.75 = 127.5 miles

Now calculate relative speed of aircraft B: V = Vb - Va = 230 - 170 = 60 mph

Now calculate time taken for Aircraft B to catch up. ie time taken for Aircraft B to travel 127.5 miles at 60 mph: T = 127.5 / 60 = 2.125 hours


Now calculate total distance Aircraft A has travelled: Da = 170 x 2.875 (2.125 + 0.75) = 488.75 miles

Total distance Aircraft B has travelled: Db = 230 x 2.125 = 488.75 miles

Therefore, total distance both aircraft have now travelled: 488.75 + 488.75 = 977.5 miles


Time taken to meet: T = Db / Vb = 488.75 / 230 = 2.125 hours after Aircraft B departs.
This is equivalent of 127.5 minutes (2.125 x 60). So 10:45 + 127.5 minutes = 12:52:30 (12:52pm and 30 seconds).
Or
T = Da / Va = 488.75 / 170 = 2.875 hours after Aircraft A departs. 10:00 + 172.5 = 12:52:30



is descending from 8,000ft at 750ft/min. How long will it take to descend to 5,000ft.?
ANSWER: 8,000ft-5,000ft=3,000ft @ 750ft/min=4 Minutes.



1. What is 14 squared?
2. What's the square root of 150? Pick the nearest (choice of 11, 12, 13)
3. 2000 litres of jet fuel has a specific gravity of 0.75 per kg. How much does the fuel weigh?



You are travelling at 250 kts, and are at FL250. The procedure starts at 3000ft QNH. Where is the Top Of Descent Point?

[Lowspirited]

my hero, so instead of a million threads we'll have a million + 1

[Chewie von Nubbins]

A bunch of potential wannabes on pprune are worth 1.5 times a wannabe from Europe. European wannabes are worth 2 american wannabes.

If I have 15 american wannabes what are they worth in equivalent pprune wannabe numbers?

Huh? I am really lost with this statement. What does this mean?

[Creon]

is it 5 pprune?

[99jolegg]

I get 11.25, it's just a different way of expressing a currency conversion which they often use in aptitude tests.

[Ouseburn]

11.25 indeed...

[mech500]

since 1 european wannabe = 2 x no. of american wannabes
therefore, 15 american wannabes = 7.5 european wannabes

but "a bunch of Pprune wannabes" = 1.5 x no. of euopean wannabes

therefore, "a bunch of pprune wannabes'' = 1.5 x 7.5 = 11.25

11.25 corresponds to the values of a ''bunch'' of pprune wannabes, you cannot find the equivalent for a single pprune wannabe?

am i missing something?

[99jolegg]

No, it's a poorly phrased question which he wasn't expecting an answer too

Questions are more straight forward and clear in any reputable assessment.