mstram
31st Jan 2003, 17:52
Given "standard day" conditions, what is the relationship between impact pressure on a pitot tube and the indicated airspeed ?
I found this formuala :
velocity = square root of (2 x [impact pressure - static pressure] / air density).
To solve for Vel = 1, (1 what ?? .. ft/sec ?), I used Static= 14.7 lb/in^2, air_density= .00237 slug/ft^3
got impact_press = 14.701185 lb/in^2
Is that correct ? (14.701185 lb/in^2 pressure difference = 1 ft/sec ?
**** edited, note started with 14.7 ***
Is that correct ? (.001185 lb/in^2 press diff = 1 ft/sec ?
****
If so, how would I solve for Vel=XX. I realize it's a "basic" math question, but basic math is not one of my strong points ;)
Mike
I found this formuala :
velocity = square root of (2 x [impact pressure - static pressure] / air density).
To solve for Vel = 1, (1 what ?? .. ft/sec ?), I used Static= 14.7 lb/in^2, air_density= .00237 slug/ft^3
got impact_press = 14.701185 lb/in^2
Is that correct ? (14.701185 lb/in^2 pressure difference = 1 ft/sec ?
**** edited, note started with 14.7 ***
Is that correct ? (.001185 lb/in^2 press diff = 1 ft/sec ?
****
If so, how would I solve for Vel=XX. I realize it's a "basic" math question, but basic math is not one of my strong points ;)
Mike