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Transsonic2000
12th Oct 2011, 21:50
Hi there,

I'd need some help with the following question:

The relative bearing to a beacon is 270°R. Three minutes later, at a ground speed of 180 knots, it has changed to 225°R (corrected! previously 255). What was the distance of the closest point of approach of the aircraft to the beacon?

Correct answer would be 9 nm.

I just can't figure it out at the moment (perhaps it's to late, should go to bed) - there must be a formula for this :ugh:

Thanks!

Da-20 monkey
13th Oct 2011, 03:19
Are you sure the 2nd relative bearing isn't 225 degrees?

SFI145
13th Oct 2011, 06:47
For 9 nm to be the correct answer the second RB would be 225R

hvogt
13th Oct 2011, 11:08
Indeed, there seems to be an error. As the others have said, the given answer of 9 nm would make the second RB 225 degrees.

The answer to the question as it is would be 36 nm (using the 1/60 rule).

slav4o1
13th Oct 2011, 11:39
Using trigonometry I get 33.5nm :ok:

Transsonic2000
13th Oct 2011, 11:58
Thanks for the respond! Yes, you guys are right, the second RB is 225 not 255 - I guess that's contributed to human error, which proofs that one should be working on this type of question when it's to late (at night)!