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CoreyRSA
10th Jun 2010, 19:27
Hi I am wondering if you guys could help me with this question.

It goes as follows:

Weight 2400lbs,Pressure Altitude 5000ft,temp 20',dry grass runway 10kt headwind.What is the landing distance required to clear 50ft object?
A.1268
B.1478
C.1355
D.1292

I wanted to paste the graph here but i cant???
Off the graph the reading is 1465ft(total to clear 50ft) 640ft(ground roll) and at the bottom it says: decrease all distances by 10% for each 10kts headwind.Increase all distances by 10% for each 10kts tailwind.For operation on a dry grass runway increase all distances by 25% of "ground roll" figure.

Intruder
10th Jun 2010, 22:52
Do what it tells you: Find the normal distance. Subtract the headwind component. Add the grass correction. One of the answers fits.

aditya104
11th Jun 2010, 03:25
aDD 25% to ground roll which comes out 800ft i.e. an increase of 160ft to landing roll
decrease 1465 by 10%= 1318.5ft
Add the increased landing roll due to surface type=1318.5+160= 1478.5ft

My answer is (b)

Hope u got it. Let me knw if I am incorrect.