^^^which is basically one of the uniform motion equations put into words
where:
v1=50kph converts to:
50 x 1000/3600 = 13.888m/s so the units are concurrent with the acceleration
substitute into the equation:
(v2)=(v1)+(a)(t)
v2= (13.888 m/s)+ (1.5 m/s^2)(12s)
v2= 31.888 m/s
converted back:
31.888 x 3600/1000 = 114.8 kph
so for uniform motion, use:
v2=v1+(a)(t)
v2^2 = v1^2 + 2(a)(d)
d2=d1 + (v1)t +(a/2)(t^2)
a=accel
t=time
d=dist
have fun, enjoy the easy stuff while it lasts!
[This message has been edited by OnTheStep (edited 14 June 2001).]