Originally Posted by
Musician
constant acceleration is the "most efficient" way to cover the distance and ends up with the lowest final speed of all possibilities (unless deceleration is involved)
This is off the important point of the thread, but anyway . . .
The formula for constant acceleration is v = 2 * d/t - final velocity is twice the average
(Your formula using 3/2 is true for constant
power).
The
lowest final speed without deceleration is achieved by being catapulted to average velocity at the start of the takeoff run and then maintaining it.
The
important point is touched on in posts above. How much money is saved by using all the
runway, compared with using all the available
power? Would pssengers be happy about this calculation if they know of it?