Originally Posted by
Alex Whittingham
Let's have a go...
We know distance to PET = (DH)/(O+H), substituting..
(60/100)*1200 = (1200*H)/(O+H) therefore
(60/100) = H/(O+H) and, if we wanted to, we could find O in terms of H
also distance to PSR = EO'H/(O'+H), using O' for distance out because groundspeed out to PSR/PET may not be the same as groundspeed on from PET (engine fail case etc. - similar arguments can be presented for H not being the same as H')
substituting...
(84/100)*1200 = (8.4*O'*H)/(O'+H)
Now at this point, if O and O' were the same, we could substitute our values for O in terms of H from the first formula and find a numerical value for H. We don't know this is the case, though, and so here I stop. My comments would be (i) that this is not a fair test of knowledge of formula, rather it is a test of maths and (ii) the solution relies on an assumption that we cannot make. All comments and corrections welcome.
Could you tell us which exam this appeared in, please, and which examining State?
Hi and thanks for the answer.
I got it at the new IR Exam in South Africa. (This exam is way out of anything from the difficult level I wrote in all my CPL exams). I thought I understand FP got at my PPL and CPL exam 100%...but this at the IR Exam is way another level...I wrote it now 3 times and always got an PET/PSR question which was way out of that what you learn in the theory.
Problem is it is marked with 3 to 4 points in the exam, which is quiet heavy.
Since I am writing this exams (April 2017, no one from the chopper guys in whole South Africa passed this exam and the pass rate at the fixed wings is what I saw 0-2%).
Since the CAA changed the syllabus and the questions since mid 2016 the DFE's and instructors running massively against this new exam, because only 4 of 96 DFE's passed the exam itself. But the authority say, it's ok...