Hi Keith,
May I point out a mistake in your comment on my alternative question?
You say:
<i>Now if 12 volts produces 1 ampere then the resistance of our (parallel) circuit is 12 ohms.</i>
This is totally correct, but note that this is the <b>total</b> resistance and as we have 2 identical resistances in parallel, each <b>individual</b> resistance in a parallel set-up equals 24 ohms!
Therefor, when you say,
<i>If we now connect the same 2 batteries in series, we now have 24 volts across a 12 ohm resistance. This gives a current of 2 amps.<i>
you make a mistake!
It should be:
<i>If we now connect the same batteries in series, we now have 24 volts across a 48 ohm resistance. This gives a current of 1/2 amps.</i>
You see, I didn't assume the current would stay 1 amp as you caim, however, it was you who overlooked the fact that the partition of the total resistance of the parallel set up between the 2 equal batteries would lead to a different total resistance when changing them to a setup in serie.
Needles to say that all this will now lead you straight to the correct answer on my alternative question (which is mentioned).
