From Engines post and assuming a constant deceleration
v^2=u^2+2as
130 knots is approx 66.9 m/s
distance is 100m, so deceleration is 22 (ish) m/s^2
which is 2.3g. (Various bits of rounding there).
Now I know nothing about the profiles of the arrest, but I would have thought a constant deceleration gives the minimum as any non-linear piece would (I think) imply greater deceleration at another time point.