Just reading through Performance A and i was curious of how it is possible to answer the question with this statement:
''By reducing take-of thrust. This would allow a lower value of VMCG and so the V1 could be reduced, resulting in a greater take-off weight for the same take off distance.''
My confusion is this'' a greater T/o weight for the same distance''.
As i understand, a higher weight would result in an increased T/O distance required, because of a slower acceleration.
Appreciate your efforts guys, many thanks.
The Don!