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Old 31st July 2003 | 01:12
  #5 (permalink)  
Dick Whittingham
 
Joined: Oct 2000
Posts: 461
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From: Bristol
you can solve the final equation by asuming that for small angles Cos is 1 and Sin is the same as the angle in radians. Thus the equation becomes:

120 - 500A = (500/12)

This works out as 0.156radians, 8.9deg.

I think!

Dick W
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