yes but it dosn't change the fact that max drag occurs at max speed at max thrust which is what is was trying to get at.
Think of it in energy terms.
Energy in always has to equal energy out Energy in:
Energy from the engine
Any potential energy converstions.
Energy out:
Drag which obeys the speed squared law
So for a steady state flight, climbing, decending or S and L the potential energy converstions are going to be constant.
The only 2 things left are energy from the engine and Drag
so E engine = constant + Edrag
So the Energy of the engine is directly proportional to the energy lost to drag.
So when the energy input of the engine is at its max the energy lost to drag must be at its max for whatever steady state the aircraft is in.
So as the questions, answers have no reference to changing the aircraft away from steady state. And it also states max thrust so throttle setting dosn't come into it, it just means max power output.
Sorry again for Swatton but fig 14.6 on page 111 demonstrates this quite well.
If for any reason you can decrease the drag (which i am not saying you can) the plane will then have excess energy going into the system so it will accelerate until the drag again equals the energy into the system so we are back to max thrust (energy in) equals max drag (energy out)
MJ