Originally Posted by
CONSO
1 = 1 g
2 = 1 g
3 = 1 g
assumes balloon is stationary and NOT accelerating up or down AND he does not use a fly suit or wing suit but drops like the proverbial brick
No.
2 is zero if we use the only sensible reference frame.
You can check this by fitting a g meter to the man. It will read +1/0/+1
We can go into a little more depth if you want, but if you disagree, be aware that you are arguing with Einstein, not me.
The elevator, the rocket, and gravity: the equivalence principle ? Einstein Online