CH is 120°. Deviation is +4°. Variation is 5° W. Wind correction angle is 8° Right. TT is: (choose below)
111°
127°
113°
129°
120+4-5-8=111 (T) answer a
CH is 224°. Deviation is -3°. Variation is 4° W. TH is:
217°
223°
225°
231°
224-3-4 = 217 (T) = answer a
CH is 317°. Deviation is +3°. Variation is 5° W. Wind correction angle is 10° right. TT is:
309°
305°
329°
325°
317-3-5-10 = 305 (T) answer b
CH is 098°. Deviation is +2°. Variation is -8° and drift is 5° Left. TT is:
087°
093°
097°
109°
098-2+8+5 = 087 (T) = answer a
the only problem is I would normally have applied the deviation in the opposite sense . . . .
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got all my books out and rechecked answers: setting it out in the normal way:-
103 T +4+5+8 = 120 C
223 T -3+4 = 224 C
299 T +3+5+10 = 317 C
109 T +2-8-5 = 098 C
only question 2 provides the correct answer.
Last edited by flyme273; 31st Dec 2014 at 07:48.
Reason: correction