CH is 120°. Deviation is +4°. Variation is 5° W. Wind correction angle is 8° Right. TT is: (choose below)

111°

127°

113°

129°

120+4-5-8=111 (T) answer a

CH is 224°. Deviation is -3°. Variation is 4° W. TH is:

217°

223°

225°

231°

224-3-4 = 217 (T) = answer a

CH is 317°. Deviation is +3°. Variation is 5° W. Wind correction angle is 10° right. TT is:

309°

305°

329°

325°

317-3-5-10 = 305 (T) answer b

CH is 098°. Deviation is +2°. Variation is -8° and drift is 5° Left. TT is:

087°

093°

097°

109°

098-2+8+5 = 087 (T) = answer a

the only problem is I would normally have applied the deviation in the opposite sense . . . .

----------------

got all my books out and rechecked answers: setting it out in the normal way:-

103 T +4+5+8 = 120 C

223 T -3+4 = 224 C

299 T +3+5+10 = 317 C

109 T +2-8-5 = 098 C

only question 2 provides the correct answer.

*
Last edited by flyme273; 31st Dec 2014 at 08:48.
Reason: correction
*