Probably best to post this in the ATPL questions thread - however.
Strongly recommend drawing a diagram to aid your answer however the key to the question is the 45 degree change in RB as this must mean it forms an isosceles triangle (ist)
Dist along track = 360 * 5 mins = 30 nm and due to the (ist) is also the distance from the feature.
True bearing from feature - first get everything into true and it's HEADING that matters (unless you are drawing a diagram then track is relevant also) so Hdg(T) = 165 -25 = 140(T) + the final RB of 280 = 420 - 360 = 060 true bearing of feature from a/c + 180 = 240 true bearing from feature.
So in real plotting you would draw a line 240 from feature and arc 30 miles gives you your position.
NB lots of questions like this around just look for the 45 RB difference - simples.