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Old 17th Jun 2014, 14:50
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SpannerInTheWerks
 
Join Date: Jan 2002
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Interpolate vertically within the relevant boxes and then horizontally between these adjacent boxes.

Same for temperature.

Just because you are a student on a qualifying cross-country doesn't absolve you from responsibility nor should you consider yourself any less affected by the weather!!!

Shame you haven't been taught this before today.

So, for example:

50N 05W

05 050 25 +07
02 040 15 +13

50N 0230W

05 040 25 +09
02 040 20 +13

For 3000ft (vertically) (say, in round figures):

50N 05W

03 043 18 +11

50N 0230W

03 040 22 +12

So if you're between the two points (horizontally):

03 040 20 +11

Nearest 5 degrees of wind direction is fine;
Nearest 5 knots of wind speed is fine;
temperature is above freezing (main point);

So, in this example: 03 040 20 and no known icing would be acceptable.

In more severe weather the gradients will be greater but the above will hold true in most cases.
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