Yash has suggested a correct solution.
Allow me to elaborate
1 Nm = 6080'
Ac at 120 Kts flies 2 Nm in a min = 12160'
Dist Off track (ROD)
---------------------- X 60 = Track error (Glide Path angle)
Dist to go (Dist to fly)
which is the same as
____________________ Dist to go (Dist to fly) X Track error (GP angle)
Dist Off track (ROD) = ----------------------------------------------
_______________________________________ 60
_________________ 12080' X 3.5
_____ 42280
Therefore (ROD) = --------------- = ---------- = 704.67'/min
___________________ 60
_____________ 60
This might help those who are reading this forum for help if not the ones who posted much earlier.
