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Old 12th March 2014 | 23:16
  #26 (permalink)  
keith williams
 
Joined: Jan 2011
Posts: 660
Likes: 20
From: England
underfire

You state:

The contact load portion you ref is not applicable to the OP. Contact loading assumes there are no spreaders, it is the direct contact point of the object. The OP specifically ref spreaders.
And:

You quote page 221, note the next page, 222. Contact load with spreaders and without. Note the surface area used with the spreaders.
But in the same post you have included a calculation for contact load, which includes spreaders:

Contact Load = (500 + 20 ) / 0.48 = 1084 kg/m squared.
If we apply exactly the same process to the OP we get

Contact Load = 2000 / 3 = 667 kg/m squared.
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